If f(1)=1 and f(n+1)=-5f(n)-4 then find the value of f(5) Answer:

Find f(2): We are given that f(1) = 1. We need to use the recursive formula f(n+1) = -5f(n) - 4 to find f(2). f(2) = -5f(1) - 4 f(2) = -5(1) - 4 f(2) = -5 - 4 f(2) = -9Find f(3): Now we have f(2) = -9. We will use the recursive formula again to find f(3). f(3) = -5f(2) - 4 f(3) = -5(-9) - 4 f(3) = 45 - 4 f(3) = 41Find f(4): With f(3) = 41, we apply the recursive formula to find f(4). f(4) = -5f(3) - 4 f(4) = -5(41) - 4 f(4) = -205 - 4 f(4) = -209Find f(5): Finally, we use f(4) = -209 to find f(5). f(5) = -5f(4) - 4 f(5) = -5(-209) - 4 f(5) = 1045 - 4 f(5) = 1041

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If
f(1)=1 and
f(n+1)=-5f(n)-4 then find the value of
f(5)
Answer:

If $f(1)=1$ and $f(n+1)=-5 f(n)-4$ then find the value of $f(5)$ $\newline$ Answer:

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Q. If

f(1)=1

and

f(n+1)=-5 f(n)-4

then find the value of

f(5)

\newline

Answer:

Find $f(2)$ : We are given that $f(1) = 1$ . We need to use the recursive formula $f(n+1) = -5f(n) - 4$ to find $f(2)$ .
$f(2) = -5f(1) - 4$
$f(2) = -5(1) - 4$
$f(2) = -5 - 4$
$f(2) = -9$
Find $f(3)$ : Now we have $f(2) = -9$ . We will use the recursive formula again to find $f(3)$ . $\newline$ $f(3) = -5f(2) - 4$ $\newline$ $f(3) = -5(-9) - 4$ $\newline$ $f(3) = 45 - 4$ $\newline$ $f(3) = 41$
Find $f(4)$ : With $f(3) = 41$ , we apply the recursive formula to find $f(4)$ . $\newline$ $f(4) = -5f(3) - 4$ $\newline$ $f(4) = -5(41) - 4$ $\newline$ $f(4) = -205 - 4$ $\newline$ $f(4) = -209$
Find $f(5)$ : Finally, we use $f(4) = -209$ to find $f(5)$ .
$f(5) = -5f(4) - 4$
$f(5) = -5(-209) - 4$
$f(5) = 1045 - 4$
$f(5) = 1041$