If a_(1)=4 and a_(n)=(a_(n-1))^(2)-2 then find the value of a_(4). Answer:

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If  a_(1)=4 and  a_(n)=(a_(n-1))^(2)-2 then find the value of  a_(4). Answer:

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Given terms and formula: We are given the first term of the sequence, a_(1) = 4, and the recursive formula for the sequence, a_(n) = (a_(n-1))^2 - 2. We need to find the value of the fourth term, a_(4).Find second term: First, let's find the second term, a_(2), using the recursive formula with n=2. a_(2) = (a_(1))^2 - 2 Substitute a_(1) = 4 into the formula. a_(2) = (4)^2 - 2Calculate a_(2): Calculate the value of a_(2). a_(2) = 16 - 2 a_(2) = 14 Now we have the value of the second term.Find third term: Next, let's find the third term, a_(3), using the recursive formula with n=3. a_(3) = (a_(2))^2 - 2 Substitute a_(2) = 14 into the formula. a_(3) = (14)^2 - 2Calculate a_(3): Calculate the value of a_(3). a_(3) = 196 - 2 a_(3) = 194 Now we have the value of the third term.Find fourth term: Finally, let's find the fourth term, a_(4), using the recursive formula with n=4. a_(4) = (a_(3))^2 - 2 Substitute a_(3) = 194 into the formula. a_(4) = (194)^2 - 2Calculate a_(4): Calculate the value of a_(4). a_(4) = 37636 - 2 a_(4) = 37634 Now we have the value of the fourth term.

If $a_{1}=4$ and $a_{n}=\left(a_{n-1}\right)^{2}-2$ then find the value of $a_{4}$ . $\newline$ Answer:

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If $a_{1}=4$ and $a_{n}=\left(a_{n-1}\right)^{2}-2$ then find the value of $a_{4}$ . $\newline$ Answer: