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If 
a_(1)=1 and 
a_(n)=(a_(n-1))^(2)+1 then find the value of 
a_(4).
Answer:

If a1=1 a_{1}=1 and an=(an1)2+1 a_{n}=\left(a_{n-1}\right)^{2}+1 then find the value of a4 a_{4} .\newlineAnswer:

Full solution

Q. If a1=1 a_{1}=1 and an=(an1)2+1 a_{n}=\left(a_{n-1}\right)^{2}+1 then find the value of a4 a_{4} .\newlineAnswer:
  1. Given Sequence and Formula: We are given the first term of the sequence as a1=1a_{1} = 1 and the recursive formula for the sequence as an=(an1)2+1a_{n} = (a_{n-1})^2 + 1. We need to find the value of the fourth term, a4a_{4}.
  2. Find Second Term: First, let's find the value of the second term, a2a_{2}. According to the recursive formula, a2=(a1)2+1a_{2} = (a_{1})^2 + 1.\newlineCalculation: a2=(1)2+1=1+1=2a_{2} = (1)^2 + 1 = 1 + 1 = 2.
  3. Find Third Term: Next, we find the value of the third term, a3a_{3}. Using the recursive formula, a3=(a2)2+1a_{3} = (a_{2})^2 + 1.\newlineCalculation: a3=(2)2+1=4+1=5a_{3} = (2)^2 + 1 = 4 + 1 = 5.
  4. Find Fourth Term: Finally, we calculate the value of the fourth term, a4a_{4}. Using the recursive formula, a4=(a3)2+1a_{4} = (a_{3})^2 + 1.\newlineCalculation: a4=(5)2+1=25+1=26a_{4} = (5)^2 + 1 = 25 + 1 = 26.

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