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If 
-4x+3y=8 is a true equation, what would be the value of 
-3(-4x+3y) ?
Answer:

If 4x+3y=8 -\mathbf{4 x}+\mathbf{3 y}=8 is a true equation, what would be the value of 3(4x+3y) -\mathbf{3}(-\mathbf{4 x}+\mathbf{3 y}) ?\newlineAnswer:

Full solution

Q. If 4x+3y=8 -\mathbf{4 x}+\mathbf{3 y}=8 is a true equation, what would be the value of 3(4x+3y) -\mathbf{3}(-\mathbf{4 x}+\mathbf{3 y}) ?\newlineAnswer:
  1. Multiply by 3-3: We are given the equation 4x+3y=8-4x + 3y = 8. We need to multiply this entire equation by 3-3.\newlineCalculation: 3(4x+3y)=3×4x+3×3y-3(-4x + 3y) = -3 \times -4x + -3 \times 3y
  2. Multiply terms by 3-3: Now we will multiply each term inside the parentheses by 3-3.\newlineCalculation: 3×4x=12x-3 \times -4x = 12x and 3×3y=9y-3 \times 3y = -9y\newlineSo, 3(4x+3y)=12x9y-3(-4x + 3y) = 12x - 9y
  3. Apply equation property: Since 4x+3y=8-4x + 3y = 8 is a true equation, when we multiply both sides by 3-3, the right side of the equation also gets multiplied by 3-3.\newlineCalculation: 3(4x+3y)=3(8)-3(-4x + 3y) = -3(8)
  4. Calculate final result: Now we will multiply 3-3 by 88.\newlineCalculation: 3×8=24-3 \times 8 = -24\newlineSo, 3(4x+3y)=24-3(-4x + 3y) = -24

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