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If 
3y^(2)+x^(2)y+3=3x then find 
(dy)/(dx) in terms of 
x and 
y.
Answer: 
(dy)/(dx)=

If 3y2+x2y+3=3x 3 y^{2}+x^{2} y+3=3 x then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=

Full solution

Q. If 3y2+x2y+3=3x 3 y^{2}+x^{2} y+3=3 x then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=
  1. Given Equation: We are given the equation 3y2+x2y+3=3x3y^2 + x^2y + 3 = 3x, and we need to find the derivative of yy with respect to xx, which is denoted as (dydx)(\frac{dy}{dx}). To do this, we will use implicit differentiation, which involves taking the derivative of both sides of the equation with respect to xx, while treating yy as a function of xx.
  2. Implicit Differentiation: First, we differentiate the left side of the equation with respect to xx. The derivative of 3y23y^2 with respect to xx is 6y(dydx)6y(\frac{dy}{dx}), since yy is a function of xx and we apply the chain rule. The derivative of x2yx^2y with respect to xx is 2xy+x2(dydx)2xy + x^2(\frac{dy}{dx}), where we use the product rule. The derivative of the constant 33 with respect to xx is 3y23y^211.
  3. Differentiate Left Side: Now, we differentiate the right side of the equation with respect to xx. The derivative of 3x3x with respect to xx is 33.
  4. Differentiate Right Side: We now write the differentiated equation: 6ydydx+2xy+x2dydx=36y\frac{dy}{dx} + 2xy + x^2\frac{dy}{dx} = 3.
  5. Write Differentiated Equation: Next, we collect all terms involving dydx\frac{dy}{dx} on one side of the equation and the remaining terms on the other side. This gives us 6ydydx+x2dydx=32xy6y\frac{dy}{dx} + x^2\frac{dy}{dx} = 3 - 2xy.
  6. Collect Terms: We factor out dydx\frac{dy}{dx} from the left side of the equation to get dydx(6y+x2)=32xy\frac{dy}{dx}(6y + x^2) = 3 - 2xy.
  7. Factor Out: To solve for dydx\frac{dy}{dx}, we divide both sides of the equation by 6y+x26y + x^2, which gives us dydx=32xy6y+x2\frac{dy}{dx} = \frac{3 - 2xy}{6y + x^2}.

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