Q. If 3y2+x2y+3=3x then find dxdy in terms of x and y.Answer: dxdy=
Given Equation: We are given the equation 3y2+x2y+3=3x, and we need to find the derivative of y with respect to x, which is denoted as (dxdy). To do this, we will use implicit differentiation, which involves taking the derivative of both sides of the equation with respect to x, while treating y as a function of x.
Implicit Differentiation: First, we differentiate the left side of the equation with respect to x. The derivative of 3y2 with respect to x is 6y(dxdy), since y is a function of x and we apply the chain rule. The derivative of x2y with respect to x is 2xy+x2(dxdy), where we use the product rule. The derivative of the constant 3 with respect to x is 3y21.
Differentiate Left Side: Now, we differentiate the right side of the equation with respect to x. The derivative of 3x with respect to x is 3.
Differentiate Right Side: We now write the differentiated equation: 6ydxdy+2xy+x2dxdy=3.
Write Differentiated Equation: Next, we collect all terms involving dxdy on one side of the equation and the remaining terms on the other side. This gives us 6ydxdy+x2dxdy=3−2xy.
Collect Terms: We factor out dxdy from the left side of the equation to get dxdy(6y+x2)=3−2xy.
Factor Out: To solve for dxdy, we divide both sides of the equation by 6y+x2, which gives us dxdy=6y+x23−2xy.