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If 
3x+xy+5y=0 then find 
(dy)/(dx) in terms of 
x and 
y.
Answer: 
(dy)/(dx)=

If 3x+xy+5y=0 3 x+x y+5 y=0 then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=

Full solution

Q. If 3x+xy+5y=0 3 x+x y+5 y=0 then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=
  1. Given Equation: We are given the equation 3x+xy+5y=03x + xy + 5y = 0 and we need to find the derivative of yy with respect to xx, denoted as dydx\frac{dy}{dx}. To do this, we will use implicit differentiation, which involves taking the derivative of both sides of the equation with respect to xx, while treating yy as a function of xx.
  2. Differentiate 3x3x: First, differentiate the term 3x3x with respect to xx. The derivative of 3x3x with respect to xx is 33, since the derivative of xx is 11 and the constant 33 remains unchanged.
  3. Differentiate xyxy: Next, differentiate the term xyxy with respect to xx. Since this term is a product of xx and yy, we use the product rule: ddx(uv)=uv+uv\frac{d}{dx}(u\cdot v) = u'v + uv', where u=xu = x and v=yv = y. The derivative of xx with respect to xx is xyxy00, and we denote the derivative of yy with respect to xx as xyxy33. Therefore, the derivative of xyxy with respect to xx is xyxy66.
  4. Differentiate 5y5y: Now, differentiate the term 5y5y with respect to xx. Since yy is a function of xx, the derivative of 5y5y with respect to xx is 5dydx5\cdot\frac{dy}{dx}, using the constant multiple rule.
  5. Combine Derivatives: Putting it all together, the derivative of the left side of the equation 3x+xy+5y3x + xy + 5y with respect to xx is 3+y+xdydx+5dydx3 + y + x\frac{dy}{dx} + 5\frac{dy}{dx}. The derivative of the right side of the equation, which is 00, is simply 00.
  6. Isolate (dy)/(dx)(dy)/(dx): Now we have the equation 3+y+x(dy)/(dx)+5(dy)/(dx)=03 + y + x\cdot(dy)/(dx) + 5\cdot(dy)/(dx) = 0. We need to solve for (dy)/(dx)(dy)/(dx). To do this, we will group the terms containing (dy)/(dx)(dy)/(dx) on one side and the constants on the other side.
  7. Factor Out (dy)/(dx)(dy)/(dx): Subtract 33 and yy from both sides of the equation to isolate the terms containing (dy)/(dx)(dy)/(dx). This gives us x(dy)/(dx)+5(dy)/(dx)=3yx*(dy)/(dx) + 5*(dy)/(dx) = -3 - y.
  8. Solve for (dydx):</b>Factorout$(dydx)(\frac{dy}{dx}):</b> Factor out \$(\frac{dy}{dx}) from the left side of the equation to get (\frac{dy}{dx}) \cdot (x + \(5) = 3-3 - y.
  9. Solve for (dydx):</b>Factorout$(dydx)(\frac{dy}{dx}):</b> Factor out \$(\frac{dy}{dx}) from the left side of the equation to get (dydx)(x+5)=3y.(\frac{dy}{dx}) \cdot (x + 5) = -3 - y. Finally, divide both sides of the equation by (x+5)(x + 5) to solve for (dydx).(\frac{dy}{dx}). This gives us (dydx)=3yx+5.(\frac{dy}{dx}) = \frac{-3 - y}{x + 5}.

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