Q. If 3x+xy+5y=0 then find dxdy in terms of x and y.Answer: dxdy=
Given Equation: We are given the equation 3x+xy+5y=0 and we need to find the derivative of y with respect to x, denoted as dxdy. To do this, we will use implicit differentiation, which involves taking the derivative of both sides of the equation with respect to x, while treating y as a function of x.
Differentiate 3x: First, differentiate the term 3x with respect to x. The derivative of 3x with respect to x is 3, since the derivative of x is 1 and the constant 3 remains unchanged.
Differentiate xy: Next, differentiate the term xy with respect to x. Since this term is a product of x and y, we use the product rule: dxd(u⋅v)=u′v+uv′, where u=x and v=y. The derivative of x with respect to x is xy0, and we denote the derivative of y with respect to x as xy3. Therefore, the derivative of xy with respect to x is xy6.
Differentiate 5y: Now, differentiate the term 5y with respect to x. Since y is a function of x, the derivative of 5y with respect to x is 5⋅dxdy, using the constant multiple rule.
Combine Derivatives: Putting it all together, the derivative of the left side of the equation 3x+xy+5y with respect to x is 3+y+xdxdy+5dxdy. The derivative of the right side of the equation, which is 0, is simply 0.
Isolate (dy)/(dx): Now we have the equation 3+y+x⋅(dy)/(dx)+5⋅(dy)/(dx)=0. We need to solve for (dy)/(dx). To do this, we will group the terms containing (dy)/(dx) on one side and the constants on the other side.
Factor Out (dy)/(dx): Subtract 3 and y from both sides of the equation to isolate the terms containing (dy)/(dx). This gives us x∗(dy)/(dx)+5∗(dy)/(dx)=−3−y.
Solve for (dxdy):</b>Factorout$(dxdy) from the left side of the equation to get (\frac{dy}{dx}) \cdot (x + \(5) = −3 - y.
Solve for (dxdy):</b>Factorout$(dxdy) from the left side of the equation to get (dxdy)⋅(x+5)=−3−y. Finally, divide both sides of the equation by (x+5) to solve for (dxdy). This gives us (dxdy)=x+5−3−y.