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If -3x-7y=-1 is a true equation, what would be the value of -3(-3x-7y) ? Answer:

If −3x−7y=−1 -\mathbf{3 x}-\mathbf{7 y}=-\mathbf{1} is a true equation, what would be the value of −3(−3x−7y) -3(-3 x-7 y) ?\newlineAnswer:

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Q. If −3x−7y=−1 -\mathbf{3 x}-\mathbf{7 y}=-\mathbf{1} is a true equation, what would be the value of −3(−3x−7y) -3(-3 x-7 y) ?\newlineAnswer:
  1. Apply Distributive Property: We are given the equation −3x−7y=−1-3x - 7y = -1. We need to find the value of −3(−3x−7y)-3(-3x - 7y).\newlineFirst, we apply the distributive property to −3(−3x−7y)-3(-3x - 7y).\newline−3(−3x)−3(−7y)=3x+21y-3(-3x) - 3(-7y) = 3x + 21y.
  2. Substitute Given Equation: Now, we substitute the given equation −3x−7y=−1-3x - 7y = -1 into the expression 3x+21y3x + 21y. Since −3x−7y-3x - 7y equals −1-1, multiplying the entire equation by −3-3 will give us the value of 3x+21y3x + 21y. −3(−3x−7y)=−3(−1)-3(-3x - 7y) = -3(-1).
  3. Perform Multiplication: We perform the multiplication −3-3 times −1-1.−3(−1)=3-3(-1) = 3.
  4. Final Value: We have found the value of −3(−3x−7y)-3(-3x - 7y), which is 33.

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