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If 
3-5y+xy=0 then find 
(dy)/(dx) in terms of 
x and 
y.
Answer: 
(dy)/(dx)=

If 35y+xy=0 3-5 y+x y=0 then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=

Full solution

Q. If 35y+xy=0 3-5 y+x y=0 then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=
  1. Given Equation: We are given the equation 35y+xy=03 - 5y + xy = 0, and we need to find the derivative of yy with respect to xx, denoted as dydx\frac{dy}{dx}. To do this, we will use implicit differentiation, which involves taking the derivative of both sides of the equation with respect to xx, while treating yy as a function of xx.
  2. Implicit Differentiation: First, we differentiate each term of the equation with respect to xx. The derivative of the constant 33 with respect to xx is 00. The derivative of 5y-5y with respect to xx is 5dydx-5\frac{dy}{dx}, since yy is a function of xx. The derivative of xyxy with respect to xx is 3311 by using the product rule (3322, where 3333 and 3344).
  3. Differentiate Terms: Now we write the differentiated equation: 05dydx+y+xdydx=00 - 5\frac{dy}{dx} + y + x\frac{dy}{dx} = 0.
  4. Write Differentiated Equation: Next, we combine like terms to solve for dydx\frac{dy}{dx}. This gives us: 5dydx+xdydx=y-5\frac{dy}{dx} + x\frac{dy}{dx} = -y.
  5. Combine Like Terms: We factor out dydx\frac{dy}{dx} from the left side of the equation: (dydx)(5+x)=y\left(\frac{dy}{dx}\right)(-5 + x) = -y.
  6. Factor Out: Now, we solve for dydx\frac{dy}{dx} by dividing both sides of the equation by (5+x)(-5 + x): dydx=y5+x\frac{dy}{dx} = \frac{-y}{-5 + x}.

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