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If 2x78 |2x-7| \leq 8 , what is the greatest possible value of x7 |x-7| ?\newline(A) 12-12\newline(B) 00\newline(C) 1212\newline(D) 152152

Full solution

Q. If 2x78 |2x-7| \leq 8 , what is the greatest possible value of x7 |x-7| ?\newline(A) 12-12\newline(B) 00\newline(C) 1212\newline(D) 152152
  1. Understand Absolute Value Definition: We are given the inequality 2x78|2x-7|\leq 8. To solve this, we need to consider the definition of absolute value, which states that ab|a| \leq b implies bab-b \leq a \leq b. We apply this to our inequality.
  2. Separate into Two Inequalities: We rewrite the inequality as two separate inequalities: 82x78-8 \leq 2x-7 \leq 8.
  3. Solve Left Inequality: Now we solve for xx in both inequalities. Starting with the left inequality: 82x7-8 \leq 2x-7.\newlineAdd 77 to both sides to isolate the term with xx: 8+72x-8 + 7 \leq 2x.
  4. Solve Right Inequality: This simplifies to 12x-1 \leq 2x. Now divide both sides by 22 to solve for xx: 12x-\frac{1}{2} \leq x.
  5. Combine Both Inequalities: Now we solve the right inequality: 2x782x-7 \leq 8. Add 77 to both sides: 2x152x \leq 15.
  6. Find Greatest x7\lvert x-7 \rvert Value: Divide both sides by 22 to solve for xx: x152x \leq \frac{15}{2}.
  7. Calculate |x\(-7| ext{ at Endpoints: Combining both inequalities, we have } -\frac{11}{22} \leq x \leq \frac{1515}{22}. \text{This is the range of values } x \text{ can take.}
  8. Identify Calculation Mistake: Now we need to find the greatest possible value of x7|x-7|. To do this, we need to consider the distance of xx from 77 on the number line. The greatest distance will occur at the endpoints of the interval for xx.
  9. Identify Calculation Mistake: Now we need to find the greatest possible value of x7|x-7|. To do this, we need to consider the distance of xx from 77 on the number line. The greatest distance will occur at the endpoints of the interval for xx.We calculate x7|x-7| at the endpoints of the interval. First, for x=12x = -\frac{1}{2}: (12)7=7.5=7.5|(-\frac{1}{2})-7| = |-7.5| = 7.5.
  10. Identify Calculation Mistake: Now we need to find the greatest possible value of x7|x-7|. To do this, we need to consider the distance of xx from 77 on the number line. The greatest distance will occur at the endpoints of the interval for xx.We calculate x7|x-7| at the endpoints of the interval. First, for x=12x = -\frac{1}{2}: (12)7=7.5=7.5|(-\frac{1}{2})-7| = |-7.5| = 7.5.Now for x=152x = \frac{15}{2}: (152)7=7.5=7.5|(\frac{15}{2})-7| = |7.5| = 7.5.
  11. Identify Calculation Mistake: Now we need to find the greatest possible value of x7|x-7|. To do this, we need to consider the distance of xx from 77 on the number line. The greatest distance will occur at the endpoints of the interval for xx.We calculate x7|x-7| at the endpoints of the interval. First, for x=12x = -\frac{1}{2}: (12)7=7.5=7.5|(-\frac{1}{2})-7| = |-7.5| = 7.5.Now for x=152x = \frac{15}{2}: (152)7=7.5=7.5|(\frac{15}{2})-7| = |7.5| = 7.5.Both endpoints give us the same value for x7|x-7|, which is xx00. However, this value is not listed in the answer choices. We must have made a mistake in our calculations.

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