If (20y+5)(4y−30)=80y2+by−150 for all values of y where b is a constant, then which of the following is the value of b?Choose 1 answer:(A) −580(B) −40(C) 0(D) 620
Q. If (20y+5)(4y−30)=80y2+by−150 for all values of y where b is a constant, then which of the following is the value of b?Choose 1 answer:(A) −580(B) −40(C) 0(D) 620
Expand Equation: Expand the left side of the equation using the distributive property (FOIL method). (20y+5)(4y−30)=20y(4y)+20y(−30)+5(4y)−5(30)
Simplify Expanded Form: Simplify the expanded form. 80y2−600y+20y−150
Combine Like Terms: Combine like terms. 80y2−580y−150
Compare with Right Side: Compare the simplified form with the right side of the given equation.80y2−580y−150=80y2+by−150
Match Coefficients: Match the coefficients of the corresponding terms to find the value of b.−580y=by
Conclude Value of b: Conclude that b=−580.
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