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If 15h+25=d\frac{1}{5}h+25=d, which of the following expressions is equivalent to hh?\newlineChoose 11 answer:\newline(A) 15d5\frac{1}{5}d-5\newline(B) 15d+25\frac{1}{5}d+25\newline(C) 5d1255d-125\newline(D) 5d255d-25

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Q. If 15h+25=d\frac{1}{5}h+25=d, which of the following expressions is equivalent to hh?\newlineChoose 11 answer:\newline(A) 15d5\frac{1}{5}d-5\newline(B) 15d+25\frac{1}{5}d+25\newline(C) 5d1255d-125\newline(D) 5d255d-25
  1. Given equation: We are given the equation 15h+25=d\frac{1}{5}h + 25 = d. To find an expression equivalent to hh in terms of dd, we need to isolate hh on one side of the equation.
  2. Isolating hh: Subtract 2525 from both sides of the equation to move the constant term to the other side.\newline(15)h+2525=d25(\frac{1}{5})h + 25 - 25 = d - 25\newlineThis simplifies to:\newline(15)h=d25(\frac{1}{5})h = d - 25
  3. Multiplying both sides: Multiply both sides of the equation by 55 to solve for hh.\newline5×(15)h=5×(d25)5 \times \left(\frac{1}{5}\right)h = 5 \times (d - 25)\newlineThis simplifies to:\newlineh=5d125h = 5d - 125
  4. Matching the expression: We look at the answer choices to find which one matches our expression for hh.A) \frac{1}{5}d - 5\$B) \frac{1}{5}d + 25\$C) 5d - 125\$D) 5d - 25\The correct answer is (C) \$5d - 125.

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