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If 
0=5x^(2)+5y+x^(3)y then find 
(dy)/(dx) in terms of 
x and 
y.
Answer: 
(dy)/(dx)=

If 0=5x2+5y+x3y 0=5 x^{2}+5 y+x^{3} y then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=

Full solution

Q. If 0=5x2+5y+x3y 0=5 x^{2}+5 y+x^{3} y then find dydx \frac{d y}{d x} in terms of x x and y y .\newlineAnswer: dydx= \frac{d y}{d x}=
  1. Given Equation: We are given the equation 0=5x2+5y+x3y0 = 5x^{2} + 5y + x^{3}y, and we need to find the derivative of yy with respect to xx, denoted as dydx\frac{dy}{dx}. To do this, we will use implicit differentiation, which involves taking the derivative of both sides of the equation with respect to xx, while treating yy as a function of xx.
  2. Differentiate 5x25x^{2}: First, we differentiate the term 5x25x^{2} with respect to xx. The derivative of 5x25x^{2} with respect to xx is 10x10x.
  3. Differentiate 5y5y: Next, we differentiate the term 5y5y with respect to xx. Since yy is a function of xx, we apply the chain rule and get 5dydx5\frac{dy}{dx}.
  4. Differentiate x3yx^{3}y: Now, we differentiate the term x3yx^{3}y with respect to xx. This requires the product rule since it is the product of two functions of xx. The derivative of x3yx^{3}y with respect to xx is 3x2y+x3(dydx)3x^{2}y + x^{3}(\frac{dy}{dx}).
  5. Combine Derivatives: Now we combine the derivatives we found in the previous steps and set the derivative of the entire left side of the equation equal to the derivative of the right side, which is 00. This gives us the equation 10x+5dydx+3x2y+x3dydx=010x + 5\frac{dy}{dx} + 3x^{2}y + x^{3}\frac{dy}{dx} = 0.
  6. Solve for (\frac{dy}{dx}): We need to solve for \((\frac{dy}{dx}), so we group the terms containing \((\frac{dy}{dx}) on one side and the rest on the other side. This gives us \(\(5(\frac{dy}{dx}) + x^{33}(\frac{dy}{dx}) = 10-10x - 33x^{22}y.
  7. Factor Out (dydx):</b>Factorout$(dydx)(\frac{dy}{dx}):</b> Factor out \$(\frac{dy}{dx}) from the left side of the equation to get (dydx)(5+x3)=10x3x2y(\frac{dy}{dx})(5 + x^{3}) = -10x - 3x^{2}y.
  8. Final Solution: Now, we solve for dydx\frac{dy}{dx} by dividing both sides of the equation by (5+x3)(5 + x^{3}). This gives us dydx=10x3x2y5+x3\frac{dy}{dx} = \frac{-10x - 3x^{2}y}{5 + x^{3}}.

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