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Identify the center and radius.
2.
(x-2)^(2)+(y+3)^(2)=36

Identify the center and radius. $\newline$ $(x-2)^{2}+(y+3)^{2}=36$

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Write a quadratic function from its x-intercepts and another point

Full solution

Q. Identify the center and radius.

\newline

(x-2)^{2}+(y+3)^{2}=36

Recognize standard form: Recognize the standard form of a circle's equation. $\newline$ The equation $(x-2)^2 + (y+3)^2 = 36$ is already in the standard form $(x-h)^2 + (y-k)^2 = r^2$ , where $(h, k)$ is the center and $r$ is the radius.
Identify center: Identify the center $(h, k)$ from the equation. $\newline$ From $(x-2)^2 + (y+3)^2 = 36$ , $h = 2$ and $k = -3$ . So, the center is $(2, -3)$ .
Determine radius: Determine the radius $r$ . The radius squared, $r^2$ , is $36$ . Taking the square root of both sides, $r = \sqrt{36} = 6$ .

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