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How many solutions does the system of equations below have?\newliney=2x+10y = 2x + 10\newliney=910x+109y = -\frac{9}{10}x + \frac{10}{9}\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions

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Q. How many solutions does the system of equations below have?\newliney=2x+10y = 2x + 10\newliney=910x+109y = -\frac{9}{10}x + \frac{10}{9}\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions
  1. Analyze Equations: Analyze the given system of linear equations to determine if they are parallel, intersecting, or coincident.\newlineThe first equation is y=2x+10y = 2x + 10, which is in slope-intercept form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. The slope of the first line is 22.\newlineThe second equation is y=910x+109y = -\frac{9}{10}x + \frac{10}{9}, which is also in slope-intercept form. The slope of the second line is 910-\frac{9}{10}.\newlineSince the slopes of the two lines are different (22 vs. 910-\frac{9}{10}), the lines are not parallel and must intersect at exactly one point.
  2. Determine Slopes: Since we have determined that the lines are not parallel, we can conclude that there is exactly one point of intersection. Therefore, the system of equations has one solution.

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