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How many solutions does the system of equations below have?\newliney=2x10y = -2x - 10\newliney=2x+47y = -2x + \frac{4}{7}\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions

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Q. How many solutions does the system of equations below have?\newliney=2x10y = -2x - 10\newliney=2x+47y = -2x + \frac{4}{7}\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions
  1. Analyze Equations: Analyze the given system of equations.\newlineThe system of equations is:\newliney=2x10y = -2x - 10\newliney=2x+47y = -2x + \frac{4}{7}\newlineBoth equations are in the slope-intercept form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. Compare the slopes of the two lines.
  2. Compare Slopes: Compare the slopes of the two lines.\newlineThe slope of the first line is 2-2 and the slope of the second line is also 2-2. Since the slopes are equal, the lines are either parallel or the same line.
  3. Compare Y-Intercepts: Compare the y-intercepts of the two lines.\newlineThe y-intercept of the first line is 10-10 and the y-intercept of the second line is 47\frac{4}{7}. Since the y-intercepts are different, the lines are parallel and do not intersect.
  4. Determine Solutions: Determine the number of solutions.\newlineSince the lines are parallel and have different yy-intercepts, they will never intersect. Therefore, there are no solutions to the system of equations.

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