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How many solutions does the system of equations below have?\newliney=310x+310y = \frac{3}{10}x + \frac{3}{10}\newliney=310x+310y = \frac{3}{10}x + \frac{3}{10}\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions

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Q. How many solutions does the system of equations below have?\newliney=310x+310y = \frac{3}{10}x + \frac{3}{10}\newliney=310x+310y = \frac{3}{10}x + \frac{3}{10}\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions
  1. Analyze System of Equations: Analyze the given system of equations.\newlineThe system of equations is:\newliney=310x+310y = \frac{3}{10}x + \frac{3}{10}\newliney=310x+310y = \frac{3}{10}x + \frac{3}{10}\newlineWe notice that both equations are identical.
  2. Determine Number of Solutions: Determine the number of solutions for identical equations.\newlineSince both equations are the same, every point on the line y=310x+310y = \frac{3}{10}x + \frac{3}{10} is a solution to the system. Therefore, there are infinitely many points that satisfy both equations.

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