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How many solutions does the system have? $\begin{cases} y = 4x-8 \ 4y =4x-8 \end{cases}$

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Factor out a monomial

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Q. How many solutions does the system have?

\begin{cases} y = 4x-8 \ 4y =4x-8 \end{cases}

Write Equations: Write down the system of equations. $\newline$ We have the following system of equations: $\newline$ $\begin{cases} y = 4x-8 \ 4y =4x-8 \end{cases}$
Compare Equations: Compare the two equations. $\newline$ The first equation is $y = 4x - 8$ . $\newline$ The second equation is $4y = 4x - 8$ , which can be simplified by dividing both sides by $4$ to get $y = x - 2$ . $\newline$ However, this is a mistake. We should divide the entire right side by $4$ , not just the $x$ term.

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