How does h(x) = 2^x change over the interval from x = 5 to x = 6? Choices: (A)h(x) increases by 100% (B)h(x) decreases by 2% (C)h(x) decreases by 2 (D)h(x) increases by 2%

Calculate h(x): Calculate h(x) when x = 5. h(5) = 2^5 h(5) = 32Calculate h(x): Calculate h(x) when x = 6. h(6) = 2^6 h(6) = 64Find change in h(x): Find the change in h(x) from x = 5 to x = 6. Change = h(6) - h(5) Change = 64 - 32 Change = 32Calculate percentage increase: Calculate the percentage increase from h(5) to h(6). Percentage increase = (Change / h(5)) * 100% Percentage increase = (32 / 32) * 100% Percentage increase = 1 * 100% Percentage increase = 100%

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How does $h(x) = 2^x$ change over the interval from $x = 5$ to $x = 6$ ? $\newline$ Choices: $\newline$ (A) $h(x)$ increases by $100\%$ $\newline$ (B) $h(x)$ decreases by $2\%$ $\newline$ (C) $h(x)$ decreases by $2$ $\newline$ (D) $h(x)$ increases by $2\%$

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Math Problems

Algebra 2

Transformations of absolute value functions

Full solution

Q. How does

h(x) = 2^x

change over the interval from

x = 5

x = 6

\newline

Choices:

\newline

(A)

h(x)

increases by

100\%

\newline

(B)

h(x)

decreases by

2\%

\newline

(C)

h(x)

decreases by

2

\newline

(D)

h(x)

increases by

2\%

Calculate $h(x)$ : Calculate $h(x)$ when $x = 5$ . $\newline$ $h(5) = 2^5$ $\newline$ $h(5) = 32$
Calculate $h(x)$ : Calculate $h(x)$ when $x = 6$ . $\newline$ $h(6) = 2^6$ $\newline$ $h(6) = 64$
Find change in $h(x)$ : Find the change in $h(x)$ from $x = 5$ to $x = 6$ .
Change = $h(6) - h(5)$
Change = $64 - 32$
Change = $32$
Calculate percentage increase: Calculate the percentage increase from $h(5)$ to $h(6)$ .
Percentage increase = $(\text{Change} / h(5)) \times 100\%$
Percentage increase = $(32 / 32) \times 100\%$
Percentage increase = $1 \times 100\%$
Percentage increase = $100\%$