Hailey measured a line to be 10.4 inches long. If the actual length of the line is 10.3 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Hailey measured a line to be 10.4 inches long. If the actual length of the line is 10.3 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand percent error: Understand the concept of percent error. Percent error is a measure of how inaccurate a measurement is, represented as a percentage of the actual value. The formula for percent error is: Percent Error = (|Measured Value - Actual Value| / Actual Value) × 100Identify values: Identify the measured value and the actual value. In this problem, the measured value is 10.4 inches, and the actual value is 10.3 inches.Calculate absolute difference: Calculate the absolute difference between the measured value and the actual value. Absolute difference = |Measured Value - Actual Value| = |10.4 inches - 10.3 inches| = 0.1 inchesDivide by actual value: Divide the absolute difference by the actual value. Divide 0.1 inches by 10.3 inches to get the error fraction. Error fraction = 0.1 inches / 10.3 inches ≈ 0.00970873786407767Convert to percent: Convert the error fraction to a percent. Multiply the error fraction by 100 to convert it to a percent. Percent Error = 0.00970873786407767 × 100 ≈ 0.970873786407767%Round to nearest tenth: Round the percent error to the nearest tenth of a percent. Rounding 0.970873786407767% to the nearest tenth of a percent gives us 1.0%.

Hailey measured a line to be $10$ . $4$ inches long. If the actual length of the line is $10$ . $3$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer:_________ $\%$

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Hailey measured a line to be $10$ . $4$ inches long. If the actual length of the line is $10$ . $3$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer:_________ $\%$