h(t)=−4.9t2+9.8t+39.2Kaia throws a stone vertically upward from a bridge. The height, in meters, of the stone above the water t seconds after the throw can be modeled by the quadratic function given. How many seconds after the throw does the stone hit the water?Choose 1 answer:(A) 1(B) 2(C) 4(D) 8
Q. h(t)=−4.9t2+9.8t+39.2Kaia throws a stone vertically upward from a bridge. The height, in meters, of the stone above the water t seconds after the throw can be modeled by the quadratic function given. How many seconds after the throw does the stone hit the water?Choose 1 answer:(A) 1(B) 2(C) 4(D) 8
Step 1: Set height function equal to zero: The height function h(t)=−4.9t2+9.8t+39.2 models the stone's height above the water in meters at time t seconds after the throw. To find out when the stone hits the water, we need to solve for t when h(t)=0.
Step 2: Solve quadratic equation: Set the height function equal to zero and solve for :\newlineThis is a quadratic equation in the standard form of at^222 + bt + c = 000.
Step 333: Calculate discriminant: To solve the quadratic equation, we can use the quadratic formula:\newlinet = −b±b2−4ac2a\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}2a−b±b2−4ac\newlinewhere a=−4.9a = -4.9a=−4.9, b=9.8b = 9.8b=9.8, and c=39.2c = 39.2c=39.2.
Step 444: Determine number of solutions: First, calculate the discriminant b2−4acb^2 - 4acb2−4ac:\newlineDiscriminant = (9.8)2−4(−4.9)(39.2)(9.8)^2 - 4(-4.9)(39.2)(9.8)2−4(−4.9)(39.2)\newlineDiscriminant = 96.04−(−4)(4.9)(39.2)96.04 - (-4)(4.9)(39.2)96.04−(−4)(4.9)(39.2)\newlineDiscriminant = 96.04+768.3296.04 + 768.3296.04+768.32\newlineDiscriminant = 864.36864.36864.36
Step 555: Calculate square root of discriminant: Since the discriminant is positive, there are two real solutions. Now, calculate the two possible values for t using the quadratic formula:\newlinet = \frac{{−9-9−9.888 \pm \sqrt{864864864.363636}}}{{222 \cdot −4-4−4.999}}
Step 666: Plug square root into quadratic formula: Calculate the square root of the discriminant:\newline864.36=29.4\sqrt{864.36} = 29.4864.36=29.4
Step 777: Calculate possible solutions for t: Now, plug the square root back into the quadratic formula to find the two values of t:\newlinet = \frac{{−9-9−9.888 \pm 292929.444}}{{−9-9−9.888}}
Step 888: Determine physically meaningful solution: Calculate the two possible solutions for ttt: t1=(−9.8+29.4)(−9.8)t_1 = \frac{(-9.8 + 29.4)}{(-9.8)}t1=(−9.8)(−9.8+29.4) t1=19.6(−9.8)t_1 = \frac{19.6}{(-9.8)}t1=(−9.8)19.6 t1=−2t_1 = -2t1=−2 (This solution is not physically meaningful because time cannot be negative.)
Step 999: Final answer: The positive value of ttt is the time in seconds after the throw when the stone hits the water. Therefore, the stone hits the water 444 seconds after the throw.
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