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h(t)=-4.9t^(2)+9.8 t+39.2
Kaia throws a stone vertically upward from a bridge. The height, in meters, of the stone above the water 
t seconds after the throw can be modeled by the quadratic function given. How many seconds after the throw does the stone hit the water?
Choose 1 answer:
(A) 1
(B) 2
(c) 4
(D) 8

h(t)=4.9t2+9.8t+39.2 h(t)=-4.9 t^{2}+9.8 t+39.2 \newlineKaia throws a stone vertically upward from a bridge. The height, in meters, of the stone above the water t t seconds after the throw can be modeled by the quadratic function given. How many seconds after the throw does the stone hit the water?\newlineChoose 11 answer:\newline(A) 11\newline(B) 22\newline(C) 44\newline(D) 88

Full solution

Q. h(t)=4.9t2+9.8t+39.2 h(t)=-4.9 t^{2}+9.8 t+39.2 \newlineKaia throws a stone vertically upward from a bridge. The height, in meters, of the stone above the water t t seconds after the throw can be modeled by the quadratic function given. How many seconds after the throw does the stone hit the water?\newlineChoose 11 answer:\newline(A) 11\newline(B) 22\newline(C) 44\newline(D) 88
  1. Step 11: Set height function equal to zero: The height function h(t)=4.9t2+9.8t+39.2 h(t) = -4.9t^2 + 9.8t + 39.2 models the stone's height above the water in meters at time t t seconds after the throw. To find out when the stone hits the water, we need to solve for t t when h(t)=0 h(t) = 0 .
  2. Step 22: Solve quadratic equation: Set the height function equal to zero and solve for t:\newline00 = 4-4.99t^22 + 99.88t + 3939.22\newlineThis is a quadratic equation in the standard form of at^22 + bt + c = 00.
  3. Step 33: Calculate discriminant: To solve the quadratic equation, we can use the quadratic formula:\newlinet = b±b24ac2a\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\newlinewhere a=4.9a = -4.9, b=9.8b = 9.8, and c=39.2c = 39.2.
  4. Step 44: Determine number of solutions: First, calculate the discriminant b24acb^2 - 4ac:\newlineDiscriminant = (9.8)24(4.9)(39.2)(9.8)^2 - 4(-4.9)(39.2)\newlineDiscriminant = 96.04(4)(4.9)(39.2)96.04 - (-4)(4.9)(39.2)\newlineDiscriminant = 96.04+768.3296.04 + 768.32\newlineDiscriminant = 864.36864.36
  5. Step 55: Calculate square root of discriminant: Since the discriminant is positive, there are two real solutions. Now, calculate the two possible values for t using the quadratic formula:\newlinet = \frac{{9-9.88 \pm \sqrt{864864.3636}}}{{22 \cdot 4-4.99}}
  6. Step 66: Plug square root into quadratic formula: Calculate the square root of the discriminant:\newline864.36=29.4\sqrt{864.36} = 29.4
  7. Step 77: Calculate possible solutions for t: Now, plug the square root back into the quadratic formula to find the two values of t:\newlinet = \frac{{9-9.88 \pm 2929.44}}{{9-9.88}}
  8. Step 88: Determine physically meaningful solution: Calculate the two possible solutions for tt:
    t1=(9.8+29.4)(9.8)t_1 = \frac{(-9.8 + 29.4)}{(-9.8)}
    t1=19.6(9.8)t_1 = \frac{19.6}{(-9.8)}
    t1=2t_1 = -2 (This solution is not physically meaningful because time cannot be negative.)

    t2=(9.829.4)(9.8)t_2 = \frac{(-9.8 - 29.4)}{(-9.8)}
    t2=39.2(9.8)t_2 = \frac{-39.2}{(-9.8)}
    t2=4t_2 = 4
  9. Step 99: Final answer: The positive value of tt is the time in seconds after the throw when the stone hits the water. Therefore, the stone hits the water 44 seconds after the throw.

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