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h(t)=-16.1t^(2)+100 t
The equation models
h, the height of a firework shell in feet,
t seconds after launch. What is the height, in feet, of the firework shell 2 seconds after launch?
Choose 1 answer:
(A) 135.6
(B) 167.8
(C) 232.2
(D) 264.4

$h(t)=-16.1 t^{2}+100 t$ $\newline$ The equation models $h$ , the height of a firework shell in feet, $t$ seconds after launch. What is the height, in feet, of the firework shell $2$ seconds after launch? $\newline$ Choose $1$ answer: $\newline$ (A) $135$ . $6$ $\newline$ (B) $167$ . $8$ $\newline$ (C) $232$ . $2$ $\newline$ (D) $264$ . $4$

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Solve a system of equations using any method: word problems

Full solution

Q.

h(t)=-16.1 t^{2}+100 t

\newline

The equation models

h

, the height of a firework shell in feet,

t

seconds after launch. What is the height, in feet, of the firework shell

2

seconds after launch?

\newline

Choose

1

answer:

\newline

(A)

135

.

6

\newline

(B)

167

.

8

\newline

(C)

232

.

2

\newline

(D)

264

.

4

Identify Given Equation: Identify the given equation and the time at which we need to find the height. $\newline$ The given equation is $h(t) = -16.1t^2 + 100t$ , which models the height of a firework shell in feet, $t$ seconds after launch. We need to find the height at $t = 2$ seconds.
Substitute Value of $t$ : Substitute the value of $t$ into the equation to find the height at that time. $\newline$ Using $t = 2$ seconds, we substitute it into the equation to get $h(2) = -16.1(2)^2 + 100(2)$ .
Calculate $h(2)$ : Calculate the value of $h(2)$ by performing the operations. $\newline$ First, calculate the square of $2$ , which is $2^2 = 4$ . $\newline$ Then multiply this by $-16.1$ to get $-16.1 \times 4 = -64.4$ . $\newline$ Next, multiply $100$ by $2$ to get $100 \times 2 = 200$ . $\newline$ Now, add these two results together to find the height: $h(2) = -64.4 + 200$ .
Perform Addition: Perform the addition to find the final height. $h(2) = -64.4 + 200 = 135.6$ feet.

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