Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

h(n)=-31-7(n-1)
Complete the recursive formula of 
h(n).

{:[h(1)=◻],[h(n)=h(n-1)+]:}

h(n)=317(n1) h(n)=-31-7(n-1) \newlineComplete the recursive formula of h(n) h(n) .\newlineh(1)=h(n)=h(n1)+ \begin{array}{l} h(1)=\square \\ h(n)=h(n-1)+\square \end{array}

Full solution

Q. h(n)=317(n1) h(n)=-31-7(n-1) \newlineComplete the recursive formula of h(n) h(n) .\newlineh(1)=h(n)=h(n1)+ \begin{array}{l} h(1)=\square \\ h(n)=h(n-1)+\square \end{array}
  1. Find First Term: Determine the first term of the sequence h(n)h(n). To find h(1)h(1), we substitute n=1n = 1 into the given formula h(n)=317(n1)h(n) = -31 - 7(n - 1). h(1)=317(11)h(1) = -31 - 7(1 - 1) h(1)=317(0)h(1) = -31 - 7(0) h(1)=310h(1) = -31 - 0 h(1)=31h(1) = -31
  2. Calculate Difference: Find the difference between consecutive terms of the sequence.\newlineSince the sequence is defined by h(n)=317(n1)h(n) = -31 - 7(n - 1), we can see that the sequence decreases by 77 for each increase in nn by 11. This is because the term 7(n1)-7(n - 1) decreases by 77 each time nn increases by 11.
  3. Write Recursive Formula: Write the recursive formula using the first term and the common difference.\newlineThe recursive formula for a sequence where each term is found by adding a constant difference to the previous term is given by:\newlineh(n)=h(n1)+dh(n) = h(n - 1) + d, where dd is the common difference.\newlineSince the sequence decreases by 77, d=7d = -7.\newlineTherefore, the recursive formula is:\newlineh(n)=h(n1)7h(n) = h(n - 1) - 7

More problems from Write a formula for an arithmetic sequence