h(n)=-31-7(n-1) Complete the recursive formula of h(n). {:[h(1)=],[h(n)=h(n-1)+]:}

Find h(1): First, let's find the value of h(1) by substituting n = 1 into the given formula. h(1) = -31 - 7(1 - 1) h(1) = -31 - 7(0) h(1) = -31 - 0 h(1) = -31Calculate h(2): Now, let's find h(2) to understand the pattern of the sequence. h(2) = -31 - 7(2 - 1) h(2) = -31 - 7(1) h(2) = -31 - 7 h(2) = -38Confirm pattern with h(3): We can see that going from h(1) to h(2), we subtract 7. This suggests that the recursive formula involves subtracting 7 from the previous term. To confirm this pattern, let's calculate h(3). h(3) = -31 - 7(3 - 1) h(3) = -31 - 7(2) h(3) = -31 - 14 h(3) = -45Recursive formula for h(n): Comparing h(2) to h(3), we again subtract 7 from h(2) to get h(3). This confirms that the recursive formula for h(n) is h(n) = h(n-1) - 7.

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h(n)=-31-7(n-1)
Complete the recursive formula of
h(n).

{:[h(1)=],[h(n)=h(n-1)+]:}

$h(n)=-31-7(n-1)$ $\newline$ Complete the recursive formula of $h(n)$ . $\newline$ $\begin{array}{l} h(1)=\square \\ h(n)=h(n-1)+ \end{array}$

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Math Problems

Algebra 2

Write a formula for an arithmetic sequence

Full solution

h(n)=-31-7(n-1)

\newline

Complete the recursive formula of

h(n)

\newline

\begin{array}{l} h(1)=\square \\ h(n)=h(n-1)+ \end{array}

Find $h(1)$ : First, let's find the value of $h(1)$ by substituting $n = 1$ into the given formula. $\newline$ $h(1) = -31 - 7(1 - 1)$ $\newline$ $h(1) = -31 - 7(0)$ $\newline$ $h(1) = -31 - 0$ $\newline$ $h(1) = -31$
Calculate $h(2)$ : Now, let's find $h(2)$ to understand the pattern of the sequence. $\newline$ $h(2) = -31 - 7(2 - 1)$ $\newline$ $h(2) = -31 - 7(1)$ $\newline$ $h(2) = -31 - 7$ $\newline$ $h(2) = -38$
Confirm pattern with $h(3)$ : We can see that going from $h(1)$ to $h(2)$ , we subtract $7$ . This suggests that the recursive formula involves subtracting $7$ from the previous term. To confirm this pattern, let's calculate $h(3)$ . $\newline$ $h(3) = -31 - 7(3 - 1)$ $\newline$ $h(3) = -31 - 7(2)$ $\newline$ $h(3) = -31 - 14$ $\newline$ $h(3) = -45$
Recursive formula for $h(n)$ : Comparing $h(2)$ to $h(3)$ , we again subtract $7$ from $h(2)$ to get $h(3)$ . This confirms that the recursive formula for $h(n)$ is $h(n) = h(n-1) - 7$ .