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h(n)=-13 n
Complete the recursive formula of 
h(n).

{:[h(1)=◻],[h(n)=h(n-1)+]:}

h(n)=13n h(n)=-13 n \newlineComplete the recursive formula of h(n) h(n) .\newlineh(1)=h(n)=h(n1)+ \begin{array}{l} h(1)=\square \\ h(n)=h(n-1)+ \end{array}

Full solution

Q. h(n)=13n h(n)=-13 n \newlineComplete the recursive formula of h(n) h(n) .\newlineh(1)=h(n)=h(n1)+ \begin{array}{l} h(1)=\square \\ h(n)=h(n-1)+ \end{array}
  1. Identify first term: Identify the first term of the sequence using the given explicit formula. The explicit formula is h(n)=13nh(n) = -13n. To find the first term, substitute n=1n = 1 into the formula.\newlineCalculation: h(1)=13×1=13h(1) = -13 \times 1 = -13
  2. Determine common difference: Determine the common difference between consecutive terms. Since the sequence is defined by a linear formula h(n)=13nh(n) = -13n, the common difference is the coefficient of nn, which is 13-13.
  3. Write recursive formula: Write the recursive formula using the first term and the common difference. The recursive formula has the form h(n)=h(n1)+dh(n) = h(n-1) + d, where dd is the common difference.\newlineSince we have h(1)=13h(1) = -13 and d=13d = -13, the recursive formula is h(n)=h(n1)13h(n) = h(n-1) - 13.

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