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h=3.2ℓ+82.77
An anthropologist uses the formula to estimate the height, 
h, in centimeters, of a male with an ulna bone that is 
ℓ centimeters long. Which of the following equations correctly gives the length of the ulna bone in terms of the height?
Choose 1 answer:
(A) 
ℓ=(h)/( 3.2)-82.77
(B) 
ℓ=(h-82.77)/(3.2)
(c) 
ℓ=3.2 h-82.77
(D) 
ℓ=h-(82.77)/(3.2)

h=3.2+82.77 h=3.2 \ell+82.77 \newlineAn anthropologist uses the formula to estimate the height, h h , in centimeters, of a male with an ulna bone that is \ell centimeters long. Which of the following equations correctly gives the length of the ulna bone in terms of the height?\newlineChoose 11 answer:\newline(A) =h3.282.77 \ell=\frac{h}{3.2}-82.77 \newline(B) =h82.773.2 \ell=\frac{h-82.77}{3.2} \newline(C) =3.2h82.77 \ell=3.2 h-82.77 \newline(D) =h82.773.2 \ell=h-\frac{82.77}{3.2}

Full solution

Q. h=3.2+82.77 h=3.2 \ell+82.77 \newlineAn anthropologist uses the formula to estimate the height, h h , in centimeters, of a male with an ulna bone that is \ell centimeters long. Which of the following equations correctly gives the length of the ulna bone in terms of the height?\newlineChoose 11 answer:\newline(A) =h3.282.77 \ell=\frac{h}{3.2}-82.77 \newline(B) =h82.773.2 \ell=\frac{h-82.77}{3.2} \newline(C) =3.2h82.77 \ell=3.2 h-82.77 \newline(D) =h82.773.2 \ell=h-\frac{82.77}{3.2}
  1. Isolate the Variable \ell: Rearrange the given formula to solve for \ell.\newlineTo isolate \ell, we subtract 82.7782.77 from both sides of the equation to get h82.77=3.2h - 82.77 = 3.2\ell.
  2. Divide by the Coefficient of ℓ: Divide both sides of the equation by 3.23.2 to solve for ℓ.\newlineh82.773.2=\frac{h - 82.77}{3.2} = ℓ\newline=h82.773.2ℓ = \frac{h - 82.77}{3.2}

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