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Gottfried wanted to see how contagious yawning can be. To better understand this, he conducted a social experiment by yawning in front of a random large crowd and observing how many people yawned as a result.
The relationship between the elapsed time 
t, in minutes, since Gottfried yawned, and the number of people in the crowd, 
P_("minute ")(t), who yawned as a result is modeled by the following function:

P_("minute ")(t)=5*(1.03)^(t)
Complete the following sentence about the hourly rate of change in the number of people who yawn in Gottfried's experiment.
Round your answer to two decimal places.
Every hour, the number of people who yawn in Gottfried's experiment grows by a factor of

Gottfried wanted to see how contagious yawning can be. To better understand this, he conducted a social experiment by yawning in front of a random large crowd and observing how many people yawned as a result.\newlineThe relationship between the elapsed time t t , in minutes, since Gottfried yawned, and the number of people in the crowd, Pminute (t) P_{\text {minute }}(t) , who yawned as a result is modeled by the following function:\newlinePminute (t)=5(1.03)t P_{\text {minute }}(t)=5 \cdot(1.03)^{t} \newlineComplete the following sentence about the hourly rate of change in the number of people who yawn in Gottfried's experiment.\newlineRound your answer to two decimal places.\newlineEvery hour, the number of people who yawn in Gottfried's experiment grows by a factor of

Full solution

Q. Gottfried wanted to see how contagious yawning can be. To better understand this, he conducted a social experiment by yawning in front of a random large crowd and observing how many people yawned as a result.\newlineThe relationship between the elapsed time t t , in minutes, since Gottfried yawned, and the number of people in the crowd, Pminute (t) P_{\text {minute }}(t) , who yawned as a result is modeled by the following function:\newlinePminute (t)=5(1.03)t P_{\text {minute }}(t)=5 \cdot(1.03)^{t} \newlineComplete the following sentence about the hourly rate of change in the number of people who yawn in Gottfried's experiment.\newlineRound your answer to two decimal places.\newlineEvery hour, the number of people who yawn in Gottfried's experiment grows by a factor of
  1. Understand function and task: Understand the function and what is being asked.\newlineWe are given the function Pminute(t)=5(1.03)tP_{\text{minute}}(t)=5\cdot(1.03)^{t}, which models the number of people yawning over time in minutes. We need to find the hourly rate of change, which means we need to determine how much the number of people yawning increases every hour.
  2. Convert time to hours: Convert the time from minutes to hours.\newlineSince there are 6060 minutes in an hour, we need to find the factor by which the number of people yawning increases after 6060 minutes.
  3. Substitute and calculate: Substitute t=60t = 60 into the function to find the hourly rate of change.Pminute(60)=5×(1.03)60P_{\text{minute}}(60) = 5\times(1.03)^{60}Now we need to calculate (1.03)60(1.03)^{60}.
  4. Calculate (1.03)60(1.03)^{60}: Calculate (1.03)60(1.03)^{60} using a calculator.\newline(1.03)605.892(1.03)^{60} \approx 5.892
  5. Multiply to find total: Multiply the result by the initial number of people (55) to find the number of people who yawn after one hour.\newlinePminute(60)=5×5.892P_{\text{minute}}(60) = 5 \times 5.892\newlinePminute(60)29.46P_{\text{minute}}(60) \approx 29.46
  6. Determine hourly rate: Determine the hourly rate of change.\newlineThe hourly rate of change is the factor by which the number of people increases every hour. Since we started with 55 people and ended up with approximately 29.4629.46 people after one hour, we divide the final amount by the initial amount to find the rate of change.\newlineHourly rate of change = Pminute(60)/5P_{\text{minute}}(60) / 5\newlineHourly rate of change 29.46/5\approx 29.46 / 5\newlineHourly rate of change 5.892\approx 5.892
  7. Round to two decimal: Round the hourly rate of change to two decimal places.\newlineHourly rate of change 5.89\approx 5.89 (rounded to two decimal places)

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