Q. Given y=3cot(2x), find dxdy.Answer: dxdy=Submit Answer
Identify Function and Rules: Identify the function to differentiate and the rules that will be applied. The function is y=3cot(2x), and we will use the chain rule and the derivative of cotangent.
Recall Cotangent Derivative: Recall the derivative of cotangent. The derivative of cot(x) with respect to x is −csc2(x), where csc is the cosecant function.
Apply Chain Rule: Apply the chain rule. The chain rule states that the derivative of a composite function f(g(x)) is f′(g(x))g′(x). Here, f(x)=3cot(x) and g(x)=2x. We need to find the derivative of f with respect to g and then multiply by the derivative of g with respect to x.
Differentiate Composite Function: Differentiate f(g(x))=3cot(g(x)) with respect to g. The derivative is −3csc2(g(x)) because the derivative of cotangent is −csc2(x), and we multiply by the constant 3.
Differentiate Linear Function: Differentiate g(x)=2x with respect to x. The derivative is 2 because the derivative of x with respect to x is 1, and we multiply by the constant 2.
Combine Derivatives: Combine the derivatives using the chain rule. Multiply the derivative of f with respect to g by the derivative of g with respect to x to get the derivative of y with respect to x. This gives us dxdy=−3csc2(2x)×2.
Simplify Final Result: Simplify the expression. Multiply −3 by 2 to get −6. The final derivative is dxdy=−6csc2(2x).
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