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Given 
x > 0, the expression 
root(3)(x^(4)) is equivalent to

x^(2)root(3)(x^(2))

x

xroot(3)(x)

x^(2)

Given x>0 , the expression x43 \sqrt[3]{x^{4}} is equivalent to\newlinex2x23 x^{2} \sqrt[3]{x^{2}} \newlinex x \newlinexx3 x \sqrt[3]{x} \newlinex2 x^{2}

Full solution

Q. Given x>0 x>0 , the expression x43 \sqrt[3]{x^{4}} is equivalent to\newlinex2x23 x^{2} \sqrt[3]{x^{2}} \newlinex x \newlinexx3 x \sqrt[3]{x} \newlinex2 x^{2}
  1. Given expression: We are given the expression x43\sqrt[3]{x^{4}}, which is the cube root of xx to the power of 44. We need to simplify this expression.
  2. Property of exponents: Using the property of exponents that says (xa/b)=xab(x^{a/b}) = \sqrt[b]{x^a}, we can rewrite the expression as x4/3x^{4/3}.
  3. Splitting the exponent: Now, we can split the exponent 43\frac{4}{3} into two parts: 43=1+13\frac{4}{3} = 1 + \frac{1}{3}. This allows us to write x43x^{\frac{4}{3}} as x1×x13x^{1} \times x^{\frac{1}{3}}.
  4. Simplify x1x^{1}: Since x1x^{1} is simply xx, we can rewrite the expression as x×x13x \times x^{\frac{1}{3}}.
  5. Final simplification: The expression x×x13x \times x^{\frac{1}{3}} can be further simplified to x×x3x \times \sqrt[3]{x}, because x13x^{\frac{1}{3}} is the cube root of xx.

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