Given the set of zeros {−5,1,±2i}, which is a polynomial of least degree in factored form with a leading coefficient of one?f(x)=(x−5)(x+1)(x2−4)f(x)=(x+5)(x−1)(x2+2)f(x)=(x−5)(x+1)(x+2i)2f(x)=(x+5)(x−1)(x2+4)
Q. Given the set of zeros {−5,1,±2i}, which is a polynomial of least degree in factored form with a leading coefficient of one?f(x)=(x−5)(x+1)(x2−4)f(x)=(x+5)(x−1)(x2+2)f(x)=(x−5)(x+1)(x+2i)2f(x)=(x+5)(x−1)(x2+4)
Identify Zeros and Factors: Identify the zeros of the polynomial and their corresponding factors.Given zeros: −5, 1, +2i, −2iCorresponding factors: (x+5), (x−1), (x−2i), (x+2i)
Complex Zeros Conjugate Pairs: Recognize that complex zeros come in conjugate pairs. Since +2i and −2i are a pair of complex conjugate zeros, their factors multiply to a quadratic polynomial with real coefficients. (x−2i)(x+2i)=x2−(2i)2=x2+4
Combine Factors for Polynomial: Combine all factors to form the polynomial of least degree.f(x)=(x+5)(x−1)(x2+4)
Match with Given Options: Check the given options to see which one matches the derived polynomial. f(x)=(x+5)(x−1)(x2+4) matches the last option.
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