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Given the function 
y=(2x^(3))/(2+x^(3)), find 
(dy)/(dx) in simplified form.
Answer: 
(dy)/(dx)=

Given the function y=2x32+x3 y=\frac{2 x^{3}}{2+x^{3}} , find dydx \frac{d y}{d x} in simplified form.\newlineAnswer: dydx= \frac{d y}{d x}=

Full solution

Q. Given the function y=2x32+x3 y=\frac{2 x^{3}}{2+x^{3}} , find dydx \frac{d y}{d x} in simplified form.\newlineAnswer: dydx= \frac{d y}{d x}=
  1. Identify Function: Identify the function that needs to be differentiated.\newlineThe function given is y=2x32+x3y=\frac{2x^{3}}{2+x^{3}}. We need to find the derivative of this function with respect to xx, which is denoted as dydx\frac{dy}{dx}.
  2. Apply Quotient Rule: Apply the quotient rule for differentiation. The quotient rule states that if we have a function y=uvy = \frac{u}{v}, where both uu and vv are functions of xx, then the derivative of yy with respect to xx is given by dydx=vdudxudvdxv2\frac{dy}{dx} = \frac{v\frac{du}{dx} - u\frac{dv}{dx}}{v^2}. Here, u=2x3u = 2x^3 and v=2+x3v = 2 + x^3.
  3. Differentiate uu and vv: Differentiate uu and vv with respect to xx. The derivative of u=2x3u = 2x^3 with respect to xx is dudx=6x2\frac{du}{dx} = 6x^2. The derivative of v=2+x3v = 2 + x^3 with respect to xx is vv00.
  4. Substitute Derivatives: Substitute the derivatives into the quotient rule formula.\newlineUsing the derivatives from Step 33, we substitute into the quotient rule formula:\newlinedydx=(2+x3)(6x2)(2x3)(3x2)(2+x3)2\frac{dy}{dx} = \frac{(2 + x^3)(6x^2) - (2x^3)(3x^2)}{(2 + x^3)^2}.
  5. Simplify Expression: Simplify the expression.\newline(dydx)=12x2+6x56x54+4x3+x6(\frac{dy}{dx}) = \frac{12x^2 + 6x^5 - 6x^5}{4 + 4x^3 + x^6}.\newlineThis simplifies to (dydx)=12x24+4x3+x6(\frac{dy}{dx}) = \frac{12x^2}{4 + 4x^3 + x^6}.
  6. Factor Out Common Terms: Further simplify the expression by factoring out common terms if possible.\newlineWe can factor out a 44 from the numerator and denominator:\newlinedydx=4×3x24×(1+x3+(14)x6)\frac{dy}{dx} = \frac{4 \times 3x^2}{4 \times (1 + x^3 + (\frac{1}{4})x^6)}.\newlineThis simplifies to dydx=3x21+x3+(14)x6\frac{dy}{dx} = \frac{3x^2}{1 + x^3 + (\frac{1}{4})x^6}.

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