Q. Given the function y=3+x2x3+1, find dxdy in simplified form.Answer: dxdy=
Identify Function: Identify the function that needs to be differentiated.We are given the function y=3+x2x3+1, and we need to find its derivative with respect to x, which is denoted as dxdy.
Apply Quotient Rule: Apply the quotient rule for differentiation.The quotient rule states that if we have a function y=vu, where both u and v are functions of x, then the derivative of y with respect to x is given by dxdy=v2vdxdu−udxdv. Here, u=2x3+1 and v=3+x.
Differentiate u: Differentiate u with respect to x. The derivative of u=2x3+1 with respect to x is dxdu=6x2.
Differentiate v: Differentiate v with respect to x. The derivative of v=3+x with respect to x is dxdv=1.
Apply Quotient Rule: Apply the quotient rule using the derivatives from steps 3 and 4.Substitute the derivatives into the quotient rule formula to get dxdy=(3+x)2(3+x)(6x2)−(2x3+1)(1).
Simplify Expression: Simplify the expression. Expand the numerator to get (dy)/(dx)=(18x2+6x2)−(2x3+1) and simplify further.
Combine Like Terms: Combine like terms in the numerator.Combine the terms to get (dxdy=24x2−2x3−1).
Factor Numerator: Factor the numerator if possible.In this case, the numerator cannot be factored in a way that will cancel with the denominator, so we leave the expression as is.
Final Simplified Form: Write the final simplified form of the derivative.The final simplified form of the derivative is (dy)/(dx)=(24x2−2x3−1)/((3+x)2).
More problems from Find trigonometric ratios using reference angles