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Given the function 
g(x)=x^(2)-9x+12, determine the average rate of change of the function over the interval 
1 <= x <= 7.
Answer:

Given the function g(x)=x29x+12 g(x)=x^{2}-9 x+12 , determine the average rate of change of the function over the interval 1x7 1 \leq x \leq 7 .\newlineAnswer:

Full solution

Q. Given the function g(x)=x29x+12 g(x)=x^{2}-9 x+12 , determine the average rate of change of the function over the interval 1x7 1 \leq x \leq 7 .\newlineAnswer:
  1. Define function g(x)g(x): We have the function g(x)=x29x+12g(x) = x^2 - 9x + 12. We need to find the average rate of change over the interval [1,7][1, 7]. The average rate of change is calculated using the formula:\newlineAverage rate of change = (g(b)g(a))/(ba)(g(b) - g(a)) / (b - a)\newlinewhere aa and bb are the endpoints of the interval. In this case, a=1a = 1 and b=7b = 7.
  2. Calculate g(1)g(1): Calculate the value of g(1)g(1) by substituting x=1x = 1 into the function g(x)g(x).
    g(1)=(1)29(1)+12g(1) = (1)^2 - 9(1) + 12
    g(1)=19+12g(1) = 1 - 9 + 12
    g(1)=4g(1) = 4
  3. Calculate g(7)g(7): Calculate the value of g(7)g(7) by substituting x=7x = 7 into the function g(x)g(x).
    g(7)=(7)29(7)+12g(7) = (7)^2 - 9(7) + 12
    g(7)=4963+12g(7) = 49 - 63 + 12
    g(7)=14+12g(7) = -14 + 12
    g(7)=2g(7) = -2
  4. Calculate average rate of change: Now that we have g(1)g(1) and g(7)g(7), we can calculate the average rate of change using the values from Step 22 and Step 33.\newlineAverage rate of change = (g(7)g(1))/(71)(g(7) - g(1)) / (7 - 1)\newlineAverage rate of change = (24)/(71)(-2 - 4) / (7 - 1)\newlineAverage rate of change = (6)/6(-6) / 6\newlineAverage rate of change = 1-1

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