Q. Given the function f(x)=(x2−8x+9)5, find f′(x) in any form.Answer: f′(x)=
Identify Functions: First, let's identify the outer function and the inner function. The outer function is g(u)=u5 and the inner function is u(x)=x2−8x+9. We will need to find the derivative of both functions.
Derivative of Outer Function: The derivative of the outer function g(u)=u5 with respect to u is g′(u)=5u4.
Derivative of Inner Function: The derivative of the inner function u(x)=x2−8x+9 with respect to x is u′(x)=2x−8.
Apply Chain Rule: Now, we apply the chain rule. The derivative of f(x) with respect to x is f′(x)=g′(u(x))⋅u′(x). Substituting the derivatives we found, we get f′(x)=5(u(x))4⋅(2x−8).
Substitute Derivatives: Substitute u(x) back into the equation with its original expression. So, f′(x)=5(x2−8x+9)4⋅(2x−8).
Final Derivative: We have found the derivative of the function f(x) without making any mathematical errors. The derivative is f′(x)=5(x2−8x+9)4⋅(2x−8).
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