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Given the function 
f(x)=(x^(2)-8x+9)^(5), find 
f^(')(x) in any form.
Answer: 
f^(')(x)=

Given the function f(x)=(x28x+9)5 f(x)=\left(x^{2}-8 x+9\right)^{5} , find f(x) f^{\prime}(x) in any form.\newlineAnswer: f(x)= f^{\prime}(x)=

Full solution

Q. Given the function f(x)=(x28x+9)5 f(x)=\left(x^{2}-8 x+9\right)^{5} , find f(x) f^{\prime}(x) in any form.\newlineAnswer: f(x)= f^{\prime}(x)=
  1. Identify Functions: First, let's identify the outer function and the inner function. The outer function is g(u)=u5g(u)=u^5 and the inner function is u(x)=x28x+9u(x)=x^2-8x+9. We will need to find the derivative of both functions.
  2. Derivative of Outer Function: The derivative of the outer function g(u)=u5g(u)=u^5 with respect to uu is g(u)=5u4g'(u)=5u^4.
  3. Derivative of Inner Function: The derivative of the inner function u(x)=x28x+9u(x)=x^2-8x+9 with respect to xx is u(x)=2x8u'(x)=2x-8.
  4. Apply Chain Rule: Now, we apply the chain rule. The derivative of f(x)f(x) with respect to xx is f(x)=g(u(x))u(x)f'(x)=g'(u(x)) \cdot u'(x). Substituting the derivatives we found, we get f(x)=5(u(x))4(2x8)f'(x)=5(u(x))^4 \cdot (2x-8).
  5. Substitute Derivatives: Substitute u(x)u(x) back into the equation with its original expression. So, f(x)=5(x28x+9)4(2x8)f'(x)=5(x^2-8x+9)^4 \cdot (2x-8).
  6. Final Derivative: We have found the derivative of the function f(x)f(x) without making any mathematical errors. The derivative is f(x)=5(x28x+9)4(2x8)f'(x)=5(x^2-8x+9)^4 \cdot (2x-8).

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