Q. Given the function f(x)=1+5x23−x2, find f′(x) in simplified form.Answer: f′(x)=
Identify function: Identify the function to differentiate.We are given the function f(x)=1+5x23−x2. We need to find its derivative, denoted as f′(x).
Apply quotient rule: Apply the quotient rule for differentiation.The quotient rule states that if we have a function g(x)=v(x)u(x), then its derivative g′(x)=(v(x))2u′(x)v(x)−u(x)v′(x). Here, u(x)=3−x2 and v(x)=1+5x2.
Differentiate numerator: Differentiate the numerator u(x)=3−x2. The derivative of u(x) with respect to x is u′(x)=−2x.
Differentiate denominator: Differentiate the denominator v(x)=1+5x2. The derivative of v(x) with respect to x is v′(x)=10x.
Apply quotient rule: Apply the quotient rule using the derivatives from steps 3 and 4.f′(x)=(v(x))2u′(x)v(x)−u(x)v′(x) = (1+5x2)2((−2x)(1+5x2)−(3−x2)(10x))
Expand and simplify: Expand the numerator and simplify.f′(x)=(1+5x2)2−2x−10x3−30x+10x3=(1+5x2)2−2x−30x=(1+5x2)2−32x
Check for simplification: Check for any possible simplification.The expression −(1+5x2)232x is already in its simplest form.
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