Q. Given the function f(x)=2x3−23x, find f′(3). Express your answer as a single fraction in simplest radical form.Answer: f′(3)=
Rewrite function: First, we need to find the derivative of the function f(x)=2x3−23x. Let's start by rewriting the function in a form that makes it easier to differentiate.f(x)=2x213−23x21
Differentiate function: Now, let's differentiate the function using the power rule, which states that the derivative of xn with respect to x is n∗x(n−1).f′(x)=dxd[2x(1/2)3]−dxd[23x(1/2)]f′(x)=(23)∗(−21)∗x(−3/2)−(23)∗(21)∗x(−1/2)
Simplify derivative: Simplify the expression for the derivative. f′(x)=−(43)x(−23)−(43)x(−21)
Evaluate at x=3: Now, we need to evaluate the derivative at x=3.f′(3)=−(43)3(−23)−(43)3(−21)
Calculate values: Calculate the values of 3−23 and 3−21.3−23=3231=331=271=3313−21=3211=31
Substitute values: Substitute these values into the expression for f′(3).f′(3)=−(43)(331)−(43)(31)
Combine terms: Simplify the expression by combining the terms.f′(3)=−(41)(31)−(43)(31)f′(3)=−431−433f′(3)=43(−1−3)f′(3)=−434
Simplify expression: Simplify the fraction by canceling out common factors.f′(3)=−31
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