Given the function f(x)=(1)/(5)x+(6)/(5), then what is f(x-3) as a simplified polynomial? Answer:

Substitute x-3 into function: Substitute (x-3) into the function f(x). We have the function f(x) = (1/5)x + (6/5). To find f(x-3), we replace every instance of x in the function with (x-3). f(x-3) = (1/5)(x-3) + (6/5)Distribute (1/5) across terms: Distribute the (1/5) across the terms inside the parentheses. We need to multiply (1/5) by both x and -3. f(x-3) = (1/5)x - (1/5)*3 + (6/5)Simplify the expression: Simplify the expression. Now we simplify the multiplication and combine any like terms if possible. f(x-3) = (1/5)x - (3/5) + (6/5)Combine constant terms: Combine the constant terms. We have two constant terms, -(3/5) and (6/5), which we can add together. f(x-3) = (1/5)x + (6/5) - (3/5) f(x-3) = (1/5)x + (3/5)

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Given the function
f(x)=(1)/(5)x+(6)/(5), then what is
f(x-3) as a simplified polynomial?
Answer:

Given the function $f(x)=\frac{1}{5} x+\frac{6}{5}$ , then what is $f(x-3)$ as a simplified polynomial? $\newline$ Answer:

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Algebra 1

Multiplication with rational exponents

Full solution

Q. Given the function

f(x)=\frac{1}{5} x+\frac{6}{5}

, then what is

f(x-3)

as a simplified polynomial?

\newline

Answer:

Substitute $x-3$ into function: Substitute $(x-3)$ into the function $f(x)$ . We have the function $f(x) = \frac{1}{5}x + \frac{6}{5}$ . To find $f(x-3)$ , we replace every instance of $x$ in the function with $(x-3)$ . $f(x-3) = \frac{1}{5}(x-3) + \frac{6}{5}$
Distribute $(1/5)$ across terms: Distribute the $(1/5)$ across the terms inside the parentheses. $\newline$ We need to multiply $(1/5)$ by both $x$ and $-3$ . $\newline$ $f(x-3) = (1/5)x - (1/5)\times 3 + (6/5)$
Simplify the expression: Simplify the expression. $\newline$ Now we simplify the multiplication and combine any like terms if possible. $\newline$ $f(x-3) = \frac{1}{5}x - \frac{3}{5} + \frac{6}{5}$
Combine constant terms: Combine the constant terms. $\newline$ We have two constant terms, $-\frac{3}{5}$ and $\frac{6}{5}$ , which we can add together. $\newline$ $f(x-3) = \frac{1}{5}x + \frac{6}{5} - \frac{3}{5}$ $\newline$ $f(x-3) = \frac{1}{5}x + \frac{3}{5}$