Given the function f, evaluate f(-1),f(0),f(2), and f(4). f(x)={[x^(2)-3," if "x = 2]:} {:[f(-1)=" Number "],[f(0)=" Number "],[f(2)=" Number "],[f(4)=" Number "]:}

Determine f(-1): Determine which part of the piecewise function to use for f(-1) since -1 = 2, use f(x) = 4 + |x - 6|. Calculation: f(2) = 4 + |2 - 6| = 4 + 4 = 8.Determine f(4): Determine which part of the piecewise function to use for f(4) since 4 >= 2, use f(x) = 4 + |x - 6|. Calculation: f(4) = 4 + |4 - 6| = 4 + 2 = 6.

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$Given the function f, evaluate f(-1),f(0),f(2), and f(4). f(x)={[x^(2)-3," if "x < 2],[4+|x-6|," if "x >= 2]:} {:[f(-1)=" Number "],[f(0)=" Number "],[f(2)=" Number "],[f(4)=" Number "]:}$

Given the function $f$ , evaluate $f(-1), f(0), f(2)$ , and $f(4)$ . $\newline$ $f(x)=\left\{\begin{array}{cc} x^{2}-3 & \text { if } x<2 \\ 4+|x-6| & \text { if } x \geq 2 \end{array}\right.$ $\newline$ $\begin{aligned} f(-1) & =\ \\ f(0) & =\ \\ f(2) & =\ \\ f(4) & =\\ \end{aligned}$

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Math Problems

Algebra 1

Transformations of quadratic functions

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Q. Given the function

f

, evaluate

f(-1), f(0), f(2)

, and

f(4)

\newline

f(x)=\left\{\begin{array}{cc} x^{2}-3 & \text { if } x<2 \\ 4+|x-6| & \text { if } x \geq 2 \end{array}\right.

\newline

\begin{aligned} f(-1) & =\ \\ f(0) & =\ \\ f(2) & =\ \\ f(4) & =\\ \end{aligned}

Determine $f(-1)$ : Determine which part of the piecewise function to use for $f(-1)$ since -1 < 2, use $f(x) = x^2 - 3$ . $\newline$ Calculation: $f(-1) = (-1)^2 - 3 = 1 - 3 = -2$ .
Determine $f(0)$ : Determine which part of the piecewise function to use for $f(0)$ since 0 < 2, use $f(x) = x^2 - 3$ . $\newline$ Calculation: $f(0) = 0^2 - 3 = 0 - 3 = -3$ .
Determine $f(2)$ : Determine which part of the piecewise function to use for $f(2)$ since $2 \geq 2$ , use $f(x) = 4 + |x - 6|$ . $\newline$ Calculation: $f(2) = 4 + |2 - 6| = 4 + 4 = 8$ .
Determine $f(4)$ : Determine which part of the piecewise function to use for $f(4)$ since $4 \geq 2$ , use $f(x) = 4 + |x - 6|$ . $\newline$ Calculation: $f(4) = 4 + |4 - 6| = 4 + 2 = 6$ .