Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0^(@)

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Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point,  0^(@) <= theta < 360^(@).  P=((3)/(5),(4)/(5)) Answer:

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Identify Coordinates: Identify the coordinates of point P on the unit circle. The given point P has coordinates (x, y) = (3/5, 4/5). On the unit circle, these coordinates correspond to (cos(θ), sin(θ)).Determine Reference Angle: Determine the reference angle. Since both x and y coordinates are positive, point P lies in the first quadrant. The reference angle is the angle θ' that the terminal side makes with the x-axis. To find θ', we use the arccosine or arcsine function. However, since we are in the first quadrant, θ' is simply θ.Calculate Using Arccosine: Calculate the angle using the arccosine function. We use the x-coordinate (cos(θ)) to find the angle θ. Thus, θ = arccos(3/5). We calculate this using a calculator.Convert to Degrees: Convert the angle from radians to degrees. After calculating the arccosine, we get θ in radians. To convert it to degrees, we multiply by 180/π. However, since we are using a calculator, it can directly give us the angle in degrees.Round to Nearest Tenth: Round the angle to the nearest tenth of a degree. Using a calculator, we find that θ ≈ arccos(3/5) ≈ 53.13 degrees. Rounding to the nearest tenth of a degree, we get θ ≈ 53.1 degrees.

Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0^{\circ} \leq \theta<360^{\circ} . $\newline$ $P=\left(\frac{3}{5}, \frac{4}{5}\right)$ $\newline$ Answer:

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Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0^{\circ} \leq \theta<360^{\circ} .\newlineP=(35,45) P=\left(\frac{3}{5}, \frac{4}{5}\right) P=(53​,54​)\newlineAnswer:

Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0^{\circ} \leq \theta<360^{\circ} . $\newline$ $P=\left(\frac{3}{5}, \frac{4}{5}\right)$ $\newline$ Answer: