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Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 
0^(@) <= theta < 360^(@).

P=((sqrt6)/(4),-(sqrt10)/(4))
Answer:

Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0^{\circ} \leq \theta<360^{\circ} .\newlineP=(64,104) P=\left(\frac{\sqrt{6}}{4},-\frac{\sqrt{10}}{4}\right) \newlineAnswer:

Full solution

Q. Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0θ<360 0^{\circ} \leq \theta<360^{\circ} .\newlineP=(64,104) P=\left(\frac{\sqrt{6}}{4},-\frac{\sqrt{10}}{4}\right) \newlineAnswer:
  1. Calculate Tangent Ratio: To find the angle of the terminal side through the point PP on the unit circle, we need to use the inverse trigonometric functions. Since we have both the xx-coordinate (cosine value) and the yy-coordinate (sine value), we can use the arctangent function, which gives us the angle whose tangent is the ratio of the yy-coordinate to the xx-coordinate.
  2. Use Arctangent Function: First, we calculate the tangent of the angle, which is the ratio of the yy-coordinate to the xx-coordinate of the point PP.
    tan(θ)=yx=(10)/(4)(6)/(4)\tan(\theta) = \frac{y}{x} = \frac{-(\sqrt{10})/(4)}{(\sqrt{6})/(4)}
    tan(θ)=106\tan(\theta) = -\frac{\sqrt{10}}{\sqrt{6}}
    tan(θ)=106\tan(\theta) = -\sqrt{\frac{10}{6}}
    tan(θ)=53\tan(\theta) = -\sqrt{\frac{5}{3}}
  3. Consider Quadrant: Next, we use the arctangent function to find the angle whose tangent is 53-\sqrt{\frac{5}{3}}. However, since the arctangent function only gives us the principal value (between 90-90 degrees and 9090 degrees), we need to consider the quadrant in which the point PP lies to find the correct angle in the range [0,360)[0, 360) degrees.
  4. Find Angle in Radians: The point PP has a positive xx-coordinate and a negative yy-coordinate, which places it in the fourth quadrant. The arctangent of a negative number is also negative, which corresponds to an angle in the fourth quadrant. Therefore, we can use the arctangent function directly to find the angle in the fourth quadrant.\newlineθ=arctan(53)\theta = \arctan(-\sqrt{\frac{5}{3}})
  5. Convert to Degrees: Using a calculator to find the arctan(5/3)\arctan(-\sqrt{5/3}), we get an angle in radians. To convert it to degrees, we multiply by 180/π180/\pi.θ=arctan(5/3)×(180/π)\theta = \arctan(-\sqrt{5/3}) \times (180/\pi)
  6. Find Coterminal Angle: After performing the calculation, we find that the angle is approximately 58.3-58.3 degrees. However, since we want the angle in the range [0,360)[0, 360) degrees, we add 360360 degrees to the negative angle to find the positive coterminal angle.\newlineθ=58.3+360\theta = -58.3 + 360\newlineθ=301.7\theta = 301.7 degrees

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