Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Given that 
tan x=(2)/(sqrt5) and 
sin y=(4)/(5), and that angles 
x and 
y are both in Quadrant I, find the exact value of 
cos(x+y), in simplest radical form.
Answer:

Given that tanx=25 \tan x=\frac{2}{\sqrt{5}} and siny=45 \sin y=\frac{4}{5} , and that angles x x and y y are both in Quadrant I, find the exact value of cos(x+y) \cos (x+y) , in simplest radical form.\newlineAnswer:

Full solution

Q. Given that tanx=25 \tan x=\frac{2}{\sqrt{5}} and siny=45 \sin y=\frac{4}{5} , and that angles x x and y y are both in Quadrant I, find the exact value of cos(x+y) \cos (x+y) , in simplest radical form.\newlineAnswer:
  1. Find cosx\cos x: We know that tanx=25\tan x = \frac{2}{\sqrt{5}}. To find cosx\cos x, we use the identity tan2x+1=sec2x\tan^2 x + 1 = \sec^2 x, which can be rewritten as 1cos2x\frac{1}{\cos^2 x}. We can then solve for cosx\cos x.tan2x=(25)2=45\tan^2 x = \left(\frac{2}{\sqrt{5}}\right)^2 = \frac{4}{5}1+tan2x=1+45=951 + \tan^2 x = 1 + \frac{4}{5} = \frac{9}{5}Therefore, sec2x=95\sec^2 x = \frac{9}{5}, which means cos2x=59\cos^2 x = \frac{5}{9}.Since tanx=25\tan x = \frac{2}{\sqrt{5}}00 is in Quadrant I, cosx\cos x is positive, so tanx=25\tan x = \frac{2}{\sqrt{5}}22.
  2. Find cosy\cos y: We are given siny=45\sin y = \frac{4}{5}. To find cosy\cos y, we use the Pythagorean identity sin2y+cos2y=1\sin^2 y + \cos^2 y = 1. We can then solve for cosy\cos y.\newlinesin2y=(45)2=1625\sin^2 y = (\frac{4}{5})^2 = \frac{16}{25}\newline1sin2y=11625=9251 - \sin^2 y = 1 - \frac{16}{25} = \frac{9}{25}\newlineTherefore, cos2y=925\cos^2 y = \frac{9}{25}, which means cosy=925=35\cos y = \sqrt{\frac{9}{25}} = \frac{3}{5}.\newlineSince yy is in Quadrant I, cosy\cos y is positive, so siny=45\sin y = \frac{4}{5}11.
  3. Calculate cos(x+y)\cos(x+y): Now we need to find cos(x+y)\cos(x+y). We use the angle sum identity for cosine, which is cos(x+y)=cosxcosysinxsiny\cos(x+y) = \cos x \cdot \cos y - \sin x \cdot \sin y. We already have cosx=5/3\cos x = \sqrt{5}/3 and cosy=3/5\cos y = 3/5. To find sinx\sin x, we use the Pythagorean identity sin2x+cos2x=1\sin^2 x + \cos^2 x = 1. cos2x=(5/3)2=5/9\cos^2 x = (\sqrt{5}/3)^2 = 5/9 1cos2x=15/9=4/91 - \cos^2 x = 1 - 5/9 = 4/9 Therefore, sin2x=4/9\sin^2 x = 4/9, which means cos(x+y)\cos(x+y)00. Since cos(x+y)\cos(x+y)11 is in Quadrant I, sinx\sin x is positive, so cos(x+y)\cos(x+y)33.
  4. Calculate cos(x+y)\cos(x+y): Now we need to find cos(x+y)\cos(x+y). We use the angle sum identity for cosine, which is cos(x+y)=cosxcosysinxsiny\cos(x+y) = \cos x \cdot \cos y - \sin x \cdot \sin y. We already have cosx=5/3\cos x = \sqrt{5}/3 and cosy=3/5\cos y = 3/5. To find sinx\sin x, we use the Pythagorean identity sin2x+cos2x=1\sin^2 x + \cos^2 x = 1. cos2x=(5/3)2=5/9\cos^2 x = (\sqrt{5}/3)^2 = 5/9 1cos2x=15/9=4/91 - \cos^2 x = 1 - 5/9 = 4/9 Therefore, sin2x=4/9\sin^2 x = 4/9, which means cos(x+y)\cos(x+y)00. Since x is in Quadrant I, sinx\sin x is positive, so cos(x+y)\cos(x+y)22.Now we can calculate cos(x+y)\cos(x+y) using the values we have found: cos(x+y)\cos(x+y)44 cos(x+y)\cos(x+y)55 To combine these fractions, we need a common denominator, which is cos(x+y)\cos(x+y)66. cos(x+y)\cos(x+y)77 cos(x+y)\cos(x+y)88

More problems from Find trigonometric ratios using multiple identities