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Given that 
tan x=(1)/(sqrt3) and 
cos y=(sqrt5)/(5), and that angles 
x and 
y are both in Quadrant I, find the exact value of 
cos(x+y), in simplest radical form.
Answer:

Given that tanx=13 \tan x=\frac{1}{\sqrt{3}} and cosy=55 \cos y=\frac{\sqrt{5}}{5} , and that angles x x and y y are both in Quadrant I, find the exact value of cos(x+y) \cos (x+y) , in simplest radical form.\newlineAnswer:

Full solution

Q. Given that tanx=13 \tan x=\frac{1}{\sqrt{3}} and cosy=55 \cos y=\frac{\sqrt{5}}{5} , and that angles x x and y y are both in Quadrant I, find the exact value of cos(x+y) \cos (x+y) , in simplest radical form.\newlineAnswer:
  1. Use Cosine Addition Formula: To find cos(x+y)\cos(x+y), we can use the cosine addition formula: cos(x+y)=cos(x)cos(y)sin(x)sin(y)\cos(x+y) = \cos(x)\cos(y) - \sin(x)\sin(y). We already have cos(y)\cos(y), but we need to find cos(x)\cos(x) and sin(x)\sin(x) as well as sin(y)\sin(y).
  2. Find cos(x)\cos(x) and sin(x)\sin(x): Since tanx=13\tan x = \frac{1}{\sqrt{3}}, we can create a right triangle where the opposite side is 11 and the adjacent side is 3\sqrt{3}. The hypotenuse, using the Pythagorean theorem, is 12+(3)2=1+3=4=2\sqrt{1^2 + (\sqrt{3})^2} = \sqrt{1 + 3} = \sqrt{4} = 2. Therefore, cos(x)=adjacenthypotenuse=32\cos(x) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{\sqrt{3}}{2}.
  3. Find sin(y)\sin(y): Similarly, sin(x)\sin(x) can be found using the right triangle, where sin(x)=oppositehypotenuse=12\sin(x) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{1}{2}.
  4. Substitute Values: To find sin(y)\sin(y), we use the Pythagorean identity sin2(y)+cos2(y)=1\sin^2(y) + \cos^2(y) = 1. We know cos(y)=5/5\cos(y) = \sqrt{5}/5, so cos2(y)=(5/5)2=5/25=1/5\cos^2(y) = (\sqrt{5}/5)^2 = 5/25 = 1/5. Therefore, sin2(y)=11/5=4/5\sin^2(y) = 1 - 1/5 = 4/5. Since yy is in Quadrant I, sin(y)\sin(y) is positive, so sin(y)=4/5=2/5=25/5\sin(y) = \sqrt{4/5} = 2/\sqrt{5} = 2\sqrt{5}/5 after rationalizing the denominator.
  5. Simplify Expression: Now we have all the necessary values: cos(x)=3/2\cos(x) = \sqrt{3}/2, sin(x)=1/2\sin(x) = 1/2, cos(y)=5/5\cos(y) = \sqrt{5}/5, and sin(y)=25/5\sin(y) = 2\sqrt{5}/5. We can substitute these into the cosine addition formula: cos(x+y)=(3/2)(5/5)(1/2)(25/5)\cos(x+y) = (\sqrt{3}/2)(\sqrt{5}/5) - (1/2)(2\sqrt{5}/5).
  6. Final Answer: Simplify the expression: cos(x+y)=(35/10)(5/5)=(15/10)(25/10)=(1525)/10\cos(x+y) = (\sqrt{3}\sqrt{5}/10) - (\sqrt{5}/5) = (\sqrt{15}/10) - (2\sqrt{5}/10) = (\sqrt{15} - 2\sqrt{5})/10.
  7. Final Answer: Simplify the expression: cos(x+y)=(35/10)(5/5)=(15/10)(25/10)=(1525)/10\cos(x+y) = (\sqrt{3}\sqrt{5}/10) - (\sqrt{5}/5) = (\sqrt{15}/10) - (2\sqrt{5}/10) = (\sqrt{15} - 2\sqrt{5})/10. The expression (1525)/10(\sqrt{15} - 2\sqrt{5})/10 is already in simplest radical form, so this is our final answer.

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