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Given that f(x)=x+4,quad g(x)=-3x and h(x)=f(x+2)-2g(x), then what is the value of h(7) ? Answer:

Given that f(x)=x+4,g(x)=−3x f(x)=x+4, \quad g(x)=-3 x and h(x)=f(x+2)−2g(x) h(x)=f(x+2)-2 g(x) , then what is the value of h(7) h(7) ?\newlineAnswer:

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Q. Given that f(x)=x+4,g(x)=−3x f(x)=x+4, \quad g(x)=-3 x and h(x)=f(x+2)−2g(x) h(x)=f(x+2)-2 g(x) , then what is the value of h(7) h(7) ?\newlineAnswer:
  1. Find f(7+2)f(7+2): First, we need to find the value of f(x)f(x) when xx is replaced by 7+27+2, which is f(7+2)f(7+2).\newlinef(x)=x+4f(x) = x + 4\newlinef(7+2)=(7+2)+4f(7+2) = (7+2) + 4\newlinef(7+2)=7+2+4f(7+2) = 7 + 2 + 4\newlinef(7+2)=13f(7+2) = 13
  2. Find g(7)g(7): Next, we need to find the value of g(x)g(x) when xx is replaced by 77, which is g(7)g(7).\newlineg(x)=−3xg(x) = -3x\newlineg(7)=−3(7)g(7) = -3(7)\newlineg(7)=−21g(7) = -21
  3. Calculate h(7)h(7): Now, we need to calculate h(x)h(x) using the values of f(x+2)f(x+2) and g(x)g(x) we found. Since h(x)=f(x+2)−2g(x)h(x) = f(x+2) - 2g(x), we will substitute xx with 77.
    h(7)=f(7+2)−2g(7)h(7) = f(7+2) - 2g(7)
    h(7)=13−2(−21)h(7) = 13 - 2(-21)
    h(7)=13+42h(7) = 13 + 42
    h(x)h(x)00

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