Q. Given that f(x)=2x,g(x)=x−2 and h(x)=−3f(x+3)−g(x), then what is the value of h(1) ?Answer:
Write Functions Given: First, let's write down the functions given:f(x)=2xg(x)=x−2h(x)=−3f(x+3)−g(x)We need to find the value of h(1).
Find f(4): Now, let's find the value of f(x+3) when x=1.f(1+3)=f(4)=2×4=8
Calculate g(1): Next, we calculate the value of g(x) when x=1.g(1)=1−2=−1
Substitute Values into h(x): Now we can substitute the values of f(4) and g(1) into the equation for h(x) to find h(1). h(1)=−3f(1+3)−g(1) h(1)=−3×8−(−1) h(1)=−24+1
Simplify to Find h(1): Finally, we simplify the expression to find the value of h(1).h(1)=−24+1=−23
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