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Given that f(x)=-2x,g(x)=x-2 and h(x)=-2f(x)+3g(x+1), then what is the value of h(6) ? Answer:

Given that f(x)=−2x,g(x)=x−2 f(x)=-2 x, g(x)=x-2 and h(x)=−2f(x)+3g(x+1) h(x)=-2 f(x)+3 g(x+1) , then what is the value of h(6) h(6) ?\newlineAnswer:

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Q. Given that f(x)=−2x,g(x)=x−2 f(x)=-2 x, g(x)=x-2 and h(x)=−2f(x)+3g(x+1) h(x)=-2 f(x)+3 g(x+1) , then what is the value of h(6) h(6) ?\newlineAnswer:
  1. Calculate f(6)f(6): First, we need to find the value of f(6)f(6) using the function f(x)=−2xf(x) = -2x.\newlineCalculate f(6)f(6) by substituting xx with 66.\newlinef(6)=−2×6f(6) = -2 \times 6\newlinef(6)=−12f(6) = -12
  2. Find g(x+1)g(x+1): Next, we need to find the value of g(x+1)g(x+1) when xx is 66. First, calculate x+1x+1 when xx is 66.\newlinex+1=6+1x+1 = 6 + 1\newlinex+1=7x+1 = 7\newlineNow, calculate g(7)g(7) using the function g(x)=x−2g(x) = x - 2.\newlineg(7)=7−2g(7) = 7 - 2\newlineg(7)=5g(7) = 5
  3. Use values to find h(6)h(6): Now, we have the values of f(6)f(6) and g(7)g(7). We can use these to find h(6)h(6) using the function h(x)=−2f(x)+3g(x+1)h(x) = -2f(x) + 3g(x+1).\newlineSubstitute f(6)f(6) and g(7)g(7) into the function h(x)h(x).\newlineh(6)=−2(−12)+3(5)h(6) = -2(-12) + 3(5)\newlineh(6)=24+15h(6) = 24 + 15\newlinef(6)f(6)00

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