Q. Given P(A)=0.6,P(B)=0.39 and P(A∪B)=0.646, find the value of P(A∩B), rounding to the nearest thousandth, if necessary.Answer:
Formula Application: To find the probability of the intersection of two events A and B, denoted as P(A∩B), we can use the formula:P(A∩B)=P(A)+P(B)−P(A∪B)
Substitution: Now, let's plug in the given values into the formula:P(A∩B)=0.6+0.39−0.646
Calculation: Perform the calculation:P(A∩B)=0.99−0.646P(A∩B)=0.344
Final Answer: Since the problem asks for the answer rounded to the nearest thousandth, we do not need to round further as our answer is already to three decimal places.
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