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Given 
P(A)=0.39,P(B)=0.5 and 
P(A and 
B)=0.345, find the value of 
P(B∣A), rounding to the nearest thousandth, if necessary.
Answer:

Given P(A)=0.39,P(B)=0.5 P(A)=0.39, P(B)=0.5 and P(A P(A and B)=0.345 B)=0.345 , find the value of P(BA) P(B \mid A) , rounding to the nearest thousandth, if necessary.\newlineAnswer:

Full solution

Q. Given P(A)=0.39,P(B)=0.5 P(A)=0.39, P(B)=0.5 and P(A P(A and B)=0.345 B)=0.345 , find the value of P(BA) P(B \mid A) , rounding to the nearest thousandth, if necessary.\newlineAnswer:
  1. Identify Conditional Probability Formula: To find the conditional probability P(BA)P(B\mid A), we use the formula P(BA)=P(A and B)P(A)P(B\mid A) = \frac{P(A \text{ and } B)}{P(A)}. We are given P(A and B)=0.345P(A \text{ and } B) = 0.345 and P(A)=0.39P(A) = 0.39.
  2. Calculate P(BA)P(B\mid A): Now we perform the calculation using the values provided: P(BA)=0.3450.39P(B\mid A) = \frac{0.345}{0.39}.
  3. Perform Division: Calculating the division we get P(BA)=0.8846153846153846P(B\mid A) = 0.8846153846153846\ldots
  4. Round to Nearest Thousandth: Rounding to the nearest thousandth, we get P(BA)0.885P(B\mid A) \approx 0.885.

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