Gabriel measured a line to be 16.1 inches long. If the actual length of the line is 16.5 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Gabriel measured a line to be 16.1 inches long. If the actual length of the line is 16.5 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand Percent Error: Understand the concept of percent error. Percent error is a measure of how inaccurate a measurement is, compared to the true value. The formula for percent error is: Percent Error = (|Measured Value - True Value| / True Value) × 100Identify Values: Identify the measured value and the true value from the problem. Measured Value = 16.1 inches True Value = 16.5 inchesCalculate Absolute Difference: Calculate the absolute difference between the measured value and the true value. Absolute Difference = |Measured Value - True Value| Absolute Difference = |16.1 - 16.5| Absolute Difference = |-0.4| Absolute Difference = 0.4 inchesCalculate Percent Error: Calculate the percent error using the formula. Percent Error = (Absolute Difference / True Value) × 100 Percent Error = (0.4 / 16.5) × 100Perform Division and Multiplication: Perform the division and multiplication to find the percent error. Percent Error = (0.4 / 16.5) × 100 Percent Error ≈ 0.02424... × 100 Percent Error ≈ 2.424...Round Percent Error: Round the percent error to the nearest tenth of a percent. Percent Error ≈ 2.4%

Gabriel measured a line to be $16$ . $1$ inches long. If the actual length of the line is $16$ . $5$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: _______ $\%$

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Gabriel measured a line to be $16$ . $1$ inches long. If the actual length of the line is $16$ . $5$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: _______ $\%$