g(n)=-50-15 n Complete the recursive formula of g(n). {:[g(1)=◻],[g(n)=g(n-1)+]:}

Identify first term: Identify the first term of the sequence using the given explicit formula g(n) = -50 - 15n by substituting n = 1. Calculation: g(1) = -50 - 15(1) = -50 - 15 = -65.Determine common difference: Determine the common difference between consecutive terms by calculating the difference g(2) - g(1). Calculation: g(2) = -50 - 15(2) = -50 - 30 = -80, and g(1) = -65, so the common difference is -80 - (-65) = -15.Write recursive formula: Write the recursive formula using the first term and the common difference. The recursive formula has the form g(n) = g(n-1) + d, where d is the common difference. Calculation: Since the common difference is -15, the recursive formula is g(n) = g(n-1) - 15.

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g(n)=-50-15 n
Complete the recursive formula of
g(n).

{:[g(1)=◻],[g(n)=g(n-1)+]:}

$g(n)=-50-15 n$ $\newline$ Complete the recursive formula of $g(n)$ . $\newline$ $g(1)=$ $\newline$ $g(n)=g(n-1)+$

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Algebra 2

Write a formula for an arithmetic sequence

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g(n)=-50-15 n

\newline

Complete the recursive formula of

g(n)

\newline

g(1)=

\newline

g(n)=g(n-1)+

Identify first term: Identify the first term of the sequence using the given explicit formula $g(n) = -50 - 15n$ by substituting $n = 1$ . $\newline$ Calculation: $g(1) = -50 - 15(1) = -50 - 15 = -65$ .
Determine common difference: Determine the common difference between consecutive terms by calculating the difference $g(2) - g(1)$ . $\newline$ Calculation: $g(2) = -50 - 15(2) = -50 - 30 = -80$ , and $g(1) = -65$ , so the common difference is $-80 - (-65) = -15$ .
Write recursive formula: Write the recursive formula using the first term and the common difference. The recursive formula has the form $g(n) = g(n-1) + d$ , where $d$ is the common difference. $\newline$ Calculation: Since the common difference is $-15$ , the recursive formula is $g(n) = g(n-1) - 15$ .