Q. g(n)=25−49(n−1)Complete the recursive formula of g(n).
g(1) = \(\square\)
g(n) = g(n-1)+\(\square\)
Find Initial Value: To find the initial value g(1), we substitute n=1 into the given formula.g(1)=25−49(1−1)g(1)=25−49(0)g(1)=25−0g(1)=25
Find Recursive Formula: Now, we need to find the recursive formula for g(n). The recursive formula will express g(n) in terms of g(n−1). To do this, we need to understand how g(n) changes when we go from n−1 to n. g(n)=25−49(n−1) g(n−1)=25−49((n−1)−1) g(n−1)=25−49(n−2) Now, let's find the difference between g(n) and g(n−1). g(n)1 g(n)2 g(n)3 g(n)4 This means that each term is g(n)5 less than the previous term. So, the recursive formula is: g(n)6
More problems from Write a formula for an arithmetic sequence