g(n)=25-49(n-1) Complete the recursive formula of g(n). {:[g(1)=◻],[g(n)=g(n-1)+]:}

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g(n)=25-49(n-1) Complete the recursive formula of  g(n).  {:[g(1)=◻],[g(n)=g(n-1)+]:}

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Find g(1): To find the recursive formula for g(n), we first need to determine the value of g(1) by substituting n = 1 into the given function. g(1) = 25 - 49(1 - 1) g(1) = 25 - 49(0) g(1) = 25 - 0 g(1) = 25Express in terms of g(n-1): Now that we have g(1), we need to express g(n) in terms of g(n-1). We start by writing the given function for g(n) and g(n-1). g(n) = 25 - 49(n - 1) g(n-1) = 25 - 49((n-1) - 1)Simplify g(n-1): Next, we simplify the expression for g(n-1) to find a relationship between g(n) and g(n-1). g(n-1) = 25 - 49(n - 1 - 1) g(n-1) = 25 - 49(n - 2)Find the difference: Now we need to find the difference between g(n) and g(n-1) to determine the recursive part of the formula. Difference = g(n) - g(n-1) Difference = [25 - 49(n - 1)] - [25 - 49(n - 2)]Simplify the difference: We simplify the difference to find the recursive relationship. Difference = 25 - 49n + 49 - 25 + 49n - 98 Difference = -49Write the recursive formula: Since the difference between g(n) and g(n-1) is -49, we can write the recursive formula as follows: g(n) = g(n-1) - 49Combine initial condition: Finally, we combine the initial condition g(1) = 25 with the recursive relationship to complete the recursive formula. g(1) = 25 g(n) = g(n-1) - 49 for n > 1

$g(n)=25-49(n-1)$ $\newline$ Complete the recursive formula of $g(n)$ . $\newline$ $g(1)=$ $\newline$ $g(n)=g(n-1)+$

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g(n)=25−49(n−1) g(n)=25-49(n-1) g(n)=25−49(n−1)\newlineComplete the recursive formula of g(n) g(n) g(n).\newlineg(1)= g(1)= g(1)=\newlineg(n)=g(n−1)+ g(n)=g(n-1)+ g(n)=g(n−1)+

$g(n)=25-49(n-1)$ $\newline$ Complete the recursive formula of $g(n)$ . $\newline$ $g(1)=$ $\newline$ $g(n)=g(n-1)+$